Answer:
Alternate interior angles
Step-by-step explanation:
Please mark as brainliest if this has helped you
Answer:
Step-by-step explanation:
the perimeter of the semi-circle would be the diameter plus the circumference of half of the circle.
They want to know the perimeter of a square using the diameter of the sem-circle as ONE side, so the perimeter of the square would be 4 times the ONE side.
We should recall:
diameter = 2 times the radius circumference of a cirlce = 2π r
How do we find the diameter of the of the semi circle?
The perimeter of the semi circle is given as 108 cm
Perimeter of the semicirle = 2r + π r diameter plus semi circumference
108 = r ( 2 + π) factor out the r and solve for r
108 / (2 + π) = r divide both sides by ( 2 + r)
Now we know r, the perimeter of the squqre is 4 times 2r or 8r
perimeter of square = 8 [ 108 / (2 + π) ] π I used 3.14
= 864 / 5.14
= 168.1 cm I got rounded to nearest tenth
<em>When I re-checked by work I found a few math, logic and calculation errors. Please re-check my answer for any more mistakes.</em>
12f=m
It can also be m/12=f, but since it is asking for inches to feet the first one is better
1) Johnson's profit is
... net profit = selling price - costs = $155 - 35.00 - 39.17 - 36.43 = $44.40
His net earnings per hour are then
... earnings/hours = $44.40 / (4.5 h) = $9.87/h
2) net profit = selling price - overhead - cost
... net profit = selling price - 0.45 × selling price - cost . . . . substitute for overhead
... net profit = 0.55 × selling price - cost
Given that overhead = 0.45 × selling price, we can find selling price by dividing by 0.45:
... selling price = overhead/0.45
Using this in the profit equation, we have
... net profit = 0.55×(overhead/0.45) - cost
... = (0.55/0.45) × $65.34 - 49.32 . . . . . . substitute given numbers
... net profit = $30.54
Answer:
322 antes de Cristo
Step-by-step explanation:
Se começarmos com o princípio de que antes de Cristo os anos são representados em uma linha real à esquerda de 0 (nascimento de Cristo) e os anos após Cristo na linha real à direita de 0, temos:
......-384.......-322..... -2,-1,0,1,2,.......................
-384+62 = -322, isto é, o ano 322 antes (-) de Cristo