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3 years ago

The answer at the bottom is (1,3) please help

Mathematics

2 answers:

Novosadov [1.4K]3 years ago

5 0

Answer:

(3,1)

Step-by-step explanation:

Since both equations are equal to y, we can set them equal to each other

y = 3x-8

y = 4-x

3x-8 = 4-x

Add x to each side

3x+x-8 = 4-x+x

4x-8 = 4

Add 8 to each side

4x-8+8 = 4+8

4x = 12

Divide each side by 4

4x/4 =12/4

x=3

Now we can find y

y = 4-x

y = 4-3 =1

joja [24]3 years ago

5 0

Answer: y = 3x-8

y = 4-x

3x-8 = 4-x

Add x to each side

3x+x-8 = 4-x+x

4x-8 = 4

Add 8 to each side

4x-8+8 = 4+8

4x = 12

Divide each side by 4

4x/4 =12/4

x=3

Now we can find y

y = 4-x

y = 4-3 =1

Step-by-step explanation:

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3 years ago

Two of the angles of a triangle measure 40° and 100°. Classify the triangle

Ksju [112]

Hey there!

All of the given angles of a triangle will always add up to 180 degrees. Therefore, our angle measures are 100, 40, and 40. There are 3 types of triangle classifications based on angles.

Acute: all three angles are less than 90 degrees.

Right: one angle is 90 degrees.

Obtuse: has an angle that is greater than 90 degrees.

As you can see, we have one angle that is greater than 90, which is 100.

Therefore, this is an obtuse triangle.

I hope this helps!

8 0

3 years ago

Read 2 more answers

A= [1, 3; 2, 1], B=[3, 6; -1, 1]. Find AB & BA if possible

steposvetlana [31]

Answer:

$AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}$

Step-by-step explanation:

For two matrix P and Q, the product, say PQ is defined when:

The number of columns of P = The number of rows of Q

Since A is a 2×2 matrix and B is also a 2×2 matrix

Thus both AB and BA are possible.

So AB is:

$AB\Rightarrow\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\\AB\Rightarrow\quad \begin{bmatrix}3\times 1+3\times (-1) & 6\times 1+3\times 1\\3\times 2+1\times (-1) & 6\times 2+1\times 1\end{bmatrix}\\AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}$

BA is:

$BA\Rightarrow\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\\BA\Rightarrow\quad \begin{bmatrix}3\times 1+6\times 2 & 3\times 3+6\times 1\\(-1)\times 1+1\times 2 & (-1)\times 3+1\times 1\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}$