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tatiyna
3 years ago
11

Question 3: Solve this system. Use the substitution method .A .B .C .D

Mathematics
2 answers:
iren [92.7K]3 years ago
8 0
D hope this helps ._.
stealth61 [152]3 years ago
7 0

Answer:

d

Step-by-step explanation:

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Help me find the volume of the composite figure
Butoxors [25]

Answer:

V = 97.911in^3

Step-by-step explanation:

Given

Shapes: Cube and Cone

Required

Determine the volume

First we calculate the volume of the cube

V_1 = l^3

Where

l = side length = 5.1

V_1 = 5.1^3

V_1 = 132.651

Next, calculate the volume of the cone using:

V_2 = \frac{\pi r^2h}{3}

Where

h = 5.1

r = \frac{1}{2} * Diameter

r = \frac{1}{2} * 5.1

r = 2.55

So, we have:

V_2 = \frac{\pi r^2h}{3}

V_2 = \frac{\pi * 2.55^2 * 5.1}{3}

V_2 = \frac{22 * 2.55^2 * 5.1}{7*3}

V_2 = \frac{729.5805}{21}

V_2 = 34.74

The volume of the figure is:

V=V_1 - V_2

V_1 = 132.651

V = 132.651 - 34.74

V = 97.911in^3

8 0
3 years ago
Help please i give thanks lol
maks197457 [2]
What is question . .
7 0
3 years ago
Substitution would be the simplest method of solution for which system? 5/3 x = 6y and 2x -3y = 8 3x - 2y =18 and 4x + 5y =60 y
LekaFEV [45]
It would be easiest for the last one
3 0
3 years ago
Consider the following set of sample data: (34, 32, 34, 32, 40, 37, 31, 31, 29, 27). We're interested in using this data to test
rosijanka [135]

Answer:

Option I and II

Step-by-step explanation:

I. Assuming this represents a random sample from the population, the sample mean is an unbiased estimator of the population mean.

II. Because they're robust, t procedures are justified in this case.

The t procedures are utilized because they are used as a hypothesis testing tool, which allows for testing of an hypothesis applicable to a population where in this case we are testing the null hypothesis about the population mean.

7 0
3 years ago
Which of the following is equivalent to the complex number i24?
Alika [10]

Answer: 1

Step-by-step explanation:

Rewrite as (i^4)^6

Rewrite i^4 as 1

Rewrite i^4 as (i^2) ^2

((i^2)) ^2)6

Rewrite i^2 as -1

((-1) ^2) 6

Raise -1 to the power of 2

1^6

One to any power is 1.

5 0
3 years ago
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