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aev [14]
3 years ago
12

Can someone solve this for me (:

Mathematics
1 answer:
mario62 [17]3 years ago
5 0
I have no idea what the answer to that is or how to solve it but i LOVE UR PROFILE PICTURE
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6.) Find all zeros (real and complex) of the same function<br> f(x) = x4 – x3 - 5x2 - x - 6
alekssr [168]
Is this even a real question
3 0
3 years ago
Read 2 more answers
What are the solutions of the quadratic equation?
Cloud [144]
We have x^2 + 2 · x · (11/2) + (11/2)^2  = - 24 + (11/2)^2;
Then, ( x + 11/2 )^2 = -24 + 121/4;
( x + 11/2 )^2 + 96/4 - 121/4 = 0;
( x + 11/2 )^2 - 25 / 4 = 0;
( x + 11/2 )^2 - (5/2)^2 = 0;
( x + 11/2 - 5/2)·( x + 11/2 + 5/2 ) = 0;
( x + 6/2 )·( x + 16/2 ) = 0;
( x + 3 )· ( x + 8 ) = 0;
x = - 3 or x = -8;
The first choice is the correct answer.
8 0
3 years ago
Read 2 more answers
If x -1/7,evaluate x²+1/x²​
SCORPION-xisa [38]

Answer:

given \: x =  -  \frac{1}{7}

x {}^{2}  +  \frac{1}{x {}^{2} }

(  - \frac{1}{7} ) {}^{2}  +  \frac{1}{  (  - \frac{1}{7} ) {}^{2} }

\frac{1}{49}  +  \frac{1}{ \frac{1}{49} }

\frac{1}{49}  +  \frac{1 \times 49}{1}

\frac{1}{49}  + 49

\frac{2402}{49}  \: or \: 49.02

6 0
3 years ago
If your balance after 8 years in the bank at a rate of interest of 11%% is 3783193 how much was your original deposit? 29 Origin
Wittaler [7]

Answer:

The original amount deposit is $1641627.68.

Step-by-step explanation:

Given : If your balance after 8 years in the bank at a rate of interest of 11%% is 3783193.

To find : How much was your original deposit?  

Solution :

Applying interest formula,

A=P(1+r)^t

Where, A is the amount i.e. A=$3783193

P is the principal value i.e. the original deposit

r is the interest rate r=11%=0.11

t is the time t=8 years.

Substitute the value in the formula,

3783193=P(1+0.11)^8

3783193=P(1.11)^8

3783193=P\times 2.30

P=\frac{3783193}{2.30}

P=1641627.68

Therefore, The original amount deposit is $1641627.68.

3 0
3 years ago
I need help with this problem
Mekhanik [1.2K]

Answer:

divide both sides of the equation by 2/3

5 0
3 years ago
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