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Maurinko [17]
3 years ago
8

What is the solution to the system?

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0
Point slope form again

-3-9/3+1= -3

y+1=-3(x-9)

y+1=-3x+27

y=-3x+26

5+1/2+1=2

y+1=2(x+1)

y+1=2x+2

y=2x+1

For your system of equations you have

y={y=-3x+26}
y={y=2x+1}

There is a couple ways you can solve this. You could either use a subtraction method, or a substitution method. since they are both y = something i would just substitute one y in one or the other equation.

2x+1=-3x+26

5x+1=26

5x=25

x=5

So now you just plug in x = 5 for each quotation and you have your y's for both solution points

y=-3(5)+26
y=11

y=2(5)+1
y=11

So this works out nice, your solutions for the set of equations is (5,11) since they are the same points

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A friend asked you to borrow $250 and agrees to repay it with 4% interest how much interest will you earn after eight months
andrew11 [14]

Answer:

I believe in the question it only states 4% interest without any time factor so therefore it would be $10 interest for 1 month or 8 months

Is this a trick question?

Step-by-step explanation:

3 0
3 years ago
A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the
iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

Event\ 1 = \{1,2,3,4,5,6\}

Next, we list out the sample space of F

Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\

6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}

In (1): the sample space of E is:

E = \{1\}

So:

P(E) = \frac{n(E)}{n(Event\ 1)}

P(E) = \frac{1}{6}

In (2): the sample space of F is:

F = \{5,5,5,5\}

So:

P(F) = \frac{n(F)}{n(Event\ 2)}

P(F) =\frac{4}{36}

P(F) =\frac{1}{9}

For E and F to be independent:

P(E\ and\ F) = P(E) * P(F)

Substitute values for P(E) and P(F)

This gives:

P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}

P(E\ and\ F) = \frac{1}{54}

However, the actual value of P(E and F) is 0.

This is so because E = \{1\} and F = \{5,5,5,5\} have 0 common elements:

So:

P(E\ and\ F) = 0

Compare P(E\ and\ F) = \frac{1}{54} and P(E\ and\ F) = 0.

These values are not equal.

Hence: the two events are not independent

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3 years ago
There are 16 teams in a tournament. if during the first round, each team plays every other team exactly once, how many games wil
jasenka [17]
16x17=272/2=136. That is answer.
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3 years ago
4. Which of the following represents a function?
Dafna11 [192]
The 3 option
(3,9), (-7,1), (6,12), (-3, -9)
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WILL GIVE BRAINLIEST ANSWER TO THE CORRECT ONE!
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I think it would best be displayed as a line plot.
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