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Radda [10]
3 years ago
12

Which is the percent for 1.67

Mathematics
2 answers:
cluponka [151]3 years ago
7 0
The percent is 167% have a good day
cupoosta [38]3 years ago
7 0

Answer:

167%

i thank that is the anserr.

Step-by-step explanation:

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Use the unit circle to evaluate the six trigonometric functions of θ = -π.
Cerrena [4.2K]

Answer:

sin=0

cos=-1

tan=0

csc=undefined

sec=-1

cot=undefined

Step-by-step explanation:

On the unit circle, -\pi=\pi. The sin of theta is therefore 0, the cosine is -1, and the tangent is 0/-1=0. Since the following functions are just the reciprocals of the previous ones, the cosecant is 1/0=undefined, the secant is 1/-1=-1, and the cotangent is 1/0= undefined. Hope this helps!

8 0
4 years ago
Which equation results from adding the equations in this system?
S_A_V [24]

Answer:

i dont know

i am only a kid

but it is 100000000000000

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4 0
3 years ago
Read 2 more answers
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
4 years ago
A bag contains 9 red marbles, 8 green marbles and 12 blue marbles.
mina [271]

Answer:

17/29 or 58.6%

Step-by-step explanation:

P(G or R) = 8/29 + 9/29 = 17/29

5 0
3 years ago
ESTI
castortr0y [4]

Answer:

What?

Step-by-step explanation:

3 0
4 years ago
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