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3 years ago

If a square has an area of 81 square units how long is each side?

1 answer:

7 0

$A=81 \\ \\ A = s^2 \\ \\ s^2 = 81 \\ \\s=\sqrt{81} \\ \\s= 9 \\ \\ Ansewr : \ each \ side \ is \ 9 \ units \ on \ each \ side$

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Find the missing number to make the fractions equal. ?/11= 12/44

Mademuasel [1]

Answer:

Step-by-step explanation:

11x4=44

3x4=12

hope this helps :)

7 0

3 years ago

What is the solution of -8/2y-8=5/y+4-7y+8/y^2-16

Mnenie [13.5K]

<h2>Answer:</h2>

The solution of the given equation is:

y=6

<h2>Step-by-step explanation:</h2>

The expression is given by:

$\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}$

Now on solving for the given equation

$\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}$

since,

$a^2-b^2=(a-b)(a+b)\\\\so,\\\\y^2-16=y^2-4^2\\\\i.e.\\\\y^2-16=(y-4)(y+4)$

Hence, we get:

$\dfrac{-4}{y-4}=\dfrac{5\times (y-4)-(7y+8)}{(y+4)(y-4)}\\\\i.e.\\\\\dfrac{-4}{y-4}=\dfrac{5y-20-7y-8}{(y-4)(y+4)}$

$-4\times (y-4)(y+4)=(-2y-28)(y-4)\\\\i.e.\\\\(y-4)(-4\times (y+4))=(-2y-28)(y-4)\\\\i.e.\\\\(y-4)(-4y+16)=(-2y-28)(y-4)\\\\i.e.$

$(y-4)(-4y+16)-(-2y-28)(y-4)=0\\\\i.e.\\\\(y-4)(-4y-16+2y+28)=0\\\\i.e.\\\\(y-4)(-2y+12)=0\\\\i.e.$

$y-4=0\ or\ -2y+12=0\\\\i.e.\\\\y=4\ or\ 2y=12\\\\i.e.\\\\y=4\ or\ y=6$

but y≠ 4

since, the denominator of the term in the left side of the given equality and the second term in the right side of the given equality will be zero and hence, the expression will be not defined.

Hence, the value of y is: 6

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4 years ago

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How to find a circumference of a circle

Dahasolnce [82]

Answer:

2πr is the formula to calculate

Step-by-step explanation:

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3 years ago

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What is the reciprocal of -13/8 ? <br> A. 13/8<br> B.-8/13<br> C.-13/8 <br> D.8/13

erastovalidia [21]

The reciprocal is -8/13

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3 years ago

Question is on the screenshot

vesna_86 [32]

Answer: V= 150π

V= πr^2 h
V= π(5)^2 (6)
V= 150π

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3 years ago

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