Hello from MrBillDoesMath!
Answer:
108 cm^2
Discussion:
The area of the logo =
area of Trapezoid on top (I) + area of triangle on bottom (II)
I = (1/2) h ( b1 + b2) h = altitude, b1, b2 = bases
= (1/2) 6 ( 6 + 12)
= (1/2) 6 ( 18)
= 54
II = (1/2) b h
= (1/2) (12) ( 15 - 6) => altitude of triangle = 15 - 6 NOT (1/2) 15
= 54
I + II= 54 + 54 = 108
Thank you,
MrB
Answer:
a) P = (-3, 4, 3)
b) P = (7, 4, 1)
Step-by-step explanation:
a) You want Q-P = (5, 4, -1) where Q = (2, 0, 2). Solving for P, we get ...
P = Q - (5, 4, -1) = (2-5, 4-0, 2-(-1))
P = (-3, 4, 3)
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b) The vector in the opposite direction of the one given is the given one multiplied by -1.
P = Q - (-1)(5, 4, -1) = (2+5, 0+4, 2-1)
P = (7, 4, 1)
Answer:
Step-by-step explanation:
Answer:
The area of the net is not π • 9^2
:P no explanation for u
