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djverab [1.8K]
3 years ago
13

Solve the system of equations below.

Mathematics
2 answers:
Zigmanuir [339]3 years ago
4 0

Answer:

Option B is correct

(9, 3)

Step-by-step explanation:

Given the system of equations:

x-2y = 3          .....[1]

2x-3y = 9       ......[2]

Multiply equation [1] by 2 both sides we have;

2x-4y = 6               .....[3]

Subtract [3] from [2] to eliminate x we get;

2x-3y-2x+4y = 9-6

Combine like terms;

y = 3

or

y = 3

Substitute in [1] we have;

x-2(3) = 3

x -6 =3

Add 6 to both sides we have;

x = 9

Therefore, the solution for the given system of equations is, (9, 3)

Helen [10]3 years ago
3 0
Yeah it b
X=9
Y=3
So yeah
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*WILL GIVE BRAINLIEST*
Pepsi [2]

Answer:

$50 and

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Step-by-step explanation:

Question 1. Principal = $500

Rate = 5%

Time = 2yesrs

Interest = PRT /100

= 500 x 5 x 2 /100

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Interest = PRT/100

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Time = 2 years

Therefore, interest =

500 x 3 x 2 /100

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5 0
4 years ago
Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?
garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right).

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be z (x) = \cos x the base formula, where x is measured in sexagesimal degrees. This expression must be transformed by using the following data:

T = 180^{\circ} (Period)

z_{min} = -4 (Minimum)

z_{max} = 5 (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of 2\pi radians. In addition, the following considerations must be taken into account for transformations:

1) x must be replaced by \frac{2\pi\cdot x}{180^{\circ}}. (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

\Delta z = \frac{z_{max}-z_{min}}{2}

\Delta z = \frac{5+4}{2}

\Delta z = \frac{9}{2}

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

z_{m} = \frac{z_{min}+z_{max}}{2}

z_{m} = \frac{1}{2}

The new function is:

z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)

Given that z_{m} = \frac{1}{2}, \Delta z = \frac{9}{2} and T = 180^{\circ}, the outcome is:

z'(x) = \frac{1}{2}  + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

8 0
3 years ago
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aleksley [76]

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3 years ago
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34kurt

Answer:

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3 years ago
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abruzzese [7]

Answer:

Graph attached.

Step-by-step explanation:

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7 0
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