0.034833091436865 This is the answer. Sorry but can't show work
Answer:
Plot points at (0,1) and (-3,3) and draw a line going through both points.
Step-by-step explanation:
Let's start by graphing the y intercept.
y=mx+b
m is the slope. b is the y intercept. Since the equation is y=-2/3x+1, we can conclude the y intercept is 1. We graph a point at (0,1).
If you didn't know the y intercept is where the line intercepts the y-axis.
Now, from the point (0,1) we go up 2 and to the left 3 as it is a negative slope. We reach (-3,3). Plot a point there. Then draw a line going through both points. There's your line!
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.
Answer:
The expression that represents the length of 1 of the triangle's legs is y + 5
Step-by-step explanation:
An isosceles triangle has two sides equal which are the triangle legs. Let b represent the base of the triangle and l represent one of the triangle's legs. Then, the perimeter, P is given by
P = l + l + b
i.e P = 2l + b
From the question, P = 6y + 12 and b = 4y +2
∴ 6y + 12 = 2l + 4y + 2
6y - 4y + 12 - 2 = 2l
2y + 10 = 2l
∴ 2l = 2y + 10
Then,
l = (2y+10)/2
l = y + 5
Hence, the expression that represents the length of 1 of the triangle's legs is y + 5
Answer:
c(12 + 9 + 6)
12(2.25c)
Step-by-step explanation:
12c + 12 (3/4c) + 12 (1/2c)
12(1c) + 12(3/4c) + 12 (1/2c)
12(c + 3/4c + 1/2c)
12(2 1/4c)
12(2.25c)
Or
12c + 12 (3/4c) + 12 (1/2c)
12c + 9c + 6c
c(12 + 9 + 6)