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AVprozaik [17]
3 years ago
15

Coefficient of y^15x^2 in expansion of (y^3+x)^7

Mathematics
2 answers:
Hitman42 [59]3 years ago
7 0
The coefficient of y∧15×∧2 in expansion of (y∧3+x)∧7 is (15×2)+(3×7)= 51
Bess [88]3 years ago
4 0
Hello,


(x+y^{3})^7 =

x^7+7x^{6}y^{3}+21x^{5}y^{6}+35x^{4}y^{9}+35x^{3}y^{12}+21x^{2}y^{15}+7xy^{18}+y^{21}\\


Coefficient=21=2P7=7*6/2!
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Answer:

Total withholding allowances are 39.

Step-by-step explanation:

Given the gross earning of John = $743.61

It is given that 1 withholding allowance = $19

Now we have to find the total number of withholding allowances. Here, the number of withholding allowances can be determined by dividing the total earnings with $19.

Number of withholding allowances = 743.61 / 19 = 39.14 or 39 (round off).

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True or false: the square root of a number is always less than that number. Select one: A. true B. false
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Answer:

True

Step-by-step explanation:

8 0
3 years ago
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Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Sphinxa [80]

Answer:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

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Since we have given that

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Using the poisson process, we get that

(a) less than or equal to 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) equal to 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

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probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

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garik1379 [7]

Answer:

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