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3 years ago

Coefficient of y^15x^2 in expansion of (y^3+x)^7

Mathematics

2 answers:

Hitman42 [59]3 years ago

7 0

The coefficient of y∧15×∧2 in expansion of (y∧3+x)∧7 is (15×2)+(3×7)= 51

Bess [88]3 years ago

4 0

Hello,

$(x+y^{3})^7 =
$
$x^7+7x^{6}y^{3}+21x^{5}y^{6}+35x^{4}y^{9}+35x^{3}y^{12}+21x^{2}y^{15}+7xy^{18}+y^{21}\\
$

Coefficient=21=2P7=7*6/2!

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Explain your answer !! <br> Have a nice day <br><br> Will give braisnlt

Aleks [24]

Answer:

The price of hot dog is $2.5 and that of a pretzel is $1.25.

Step-by-step explanation:

Let the cost of hotdogs be h and that of pretzels be p.

So,

4h+3p = 13.75 ...(1)

and

2h+5p = 11.25 ...(2)

Multiply equation (2) by 2.

4h+10p = 22.5 ...(3)

Subtract equation (1) from (3).

4h+10p-(4h+3p) = 22.5-13.75

4h+10p-4h-3p = 8.75

7p = 8.75

y = 1.25

Put the value of y in equation (1).

4h+3(1.25) = 13.75

4h+3.75 = 13.75

4h = 13.75-3.75

4h = 10

h = 2.5

So, the price of hot dog is $2.5 and that of a pretzel is $1.25.

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2 years ago

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dexar [7]

Answer:

Yes it is possible

Step-by-step explanation:

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3 years ago

How many ways can a committee chairman choose 4 people for a subcommittee if there are 12 members on the whole committee?

Marina86 [1]

A group of k elements can be chosen from a group of n elements in $\frac{n!}{k!(n-k)!}$ ways.

$(^{12} _4)=\frac{12!}{4!(12-4)!}=\frac{12!}{4! \times 8!}=\frac{8! \times 9 \times 10 \times 11 \times 12}{2 \times 3 \times 4 \times 8!}=\frac{9 \times 10 \times 11 \times 12}{2 \times 3 \times 4}= \\ \\
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3 years ago

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Leni [432]

I guess it is simplifying the expression:

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