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3 years ago

Please help i am timed

Mathematics

2 answers:

exis [7]3 years ago

4 0

Answer:

Step-by-step explanation:

2x-10 is your answer

JulijaS [17]3 years ago

4 0

Answer:

D. 2x+5

Step-by-step explanation

All you have to do is put them all together and there you have it your answer of D 2x+5

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3 years ago

Help me pls the question is in the picture

MaRussiya [10]

Answer:

M<C = 37 degrees

M<D = 86 degrees

M<DEC = 111 degrees

Step-by-step explanation:

The exterior angle theorem can be measured by the hypotenuse of a 90 degree angle. Since there is no hypotenuse in the matrix, you don't need to make it positive :)

Therefore, after using this theorem, I came to the conclusion that m/C would be 37 degrees, since I calculated the measure of the angle. I used the same tactic on m/D and m/DEC.

I hope this helps :)

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3 years ago

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3 years ago

Read 2 more answers

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$