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3 years ago

Solve the nonlinear system of equations

Mathematics

1 answer:

Kitty [74]3 years ago

3 0

Answer:

There are no real solutions. The complex solutions are ...

(x, y) = (2.5-i√1.75, -2.5+i√1.75) or (2.5+i1.75, -2.5-i1.75)

Step-by-step explanation:

Subtract the first equation from the second.

y -y = (x^2 -6x +8) -(-x)

0 = x^2 -5x +8

Rewrite to facilitate completing the square:

x^2 -5x = -8

x^2 -5x +6.25 = -1.75 . . . . . add 6.25 to complete the square

(x -2.5)^2 = -1.75 . . . . . write as a square

x -2.5 = ±i√1.75 . . . . . . take the square root

x = 2.5 ± i√1.75 . . . . . . add 2.5; y is the opposite of this

Solutions are ...

x = 2.5 +i√1.75, y = -2.5 -i√1.75
x = 2.5 -i√1.75, y = -2.5 +i√1.75

_____

The graph shows the equations have no point of intersection, meaning there are no real solutions. The complex solutions are shown above.

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Answer:

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