Possible answers:
2
11
window
ii
Answer:
<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>
Step-by-step explanation:
1. Let's review the data given to us for solving the question:
Distance from Laura's home to her job = 4 1/2 miles
Time when Laura starts to walk to her job : 9:00 a.m.
Time when Laura is scheduled to start working : 11:00 a.m.
2. Will she arrive at her job on time?
Time Laura has to complete the distance from her home to her job = 2 hours (11 -9)
Speed that Laura need to walk to arrive to her job on time = Distance from Laura's home to her job/Time Laura has to complete the distance from her home to her job
Speed that Laura need to walk to arrive to her job on time = 4 1/2 miles/2 hours = (4 1/2)/2 = (9/2)/2 = 9/2 * 1/2 = 9/4 = 2 1/4
Speed that Laura need to walk to arrive to her job on time = 2 1/4 miles per hour.
<u>Laura has to walk at 2 1/4 miles per hour or faster to arrive to her job on time.</u>
( 4,20)is the correct answer
(x+2y)(x-5y)
do foil method:
x^2-5xy+2xy-10y^2
simplify x^2-3xy-10y^2,
so d is correct.
