Drop a perpendicular from an obtuse vertex.
That makes a 30 - 60º right triangle, with
hypotenuse 6 and short leg 3. So the long leg,
which is the height of the rhombus, is 3√3 .
Since a rhombus is a parallelogram, its area
is base x height = 6 x 3√3 = 18√3 .
Answer:
∠B = 41°
Step-by-step explanation:
∠BCD is an exterior angle of the triangle
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠A and ∠ B are the 2 opposite interior angles, hence
∠A + ∠B = 113, that is
72 + ∠B = 113 ( subtract 72 from both sides )
∠B = 41°
1. (3,2)....because when finding the slope, we find the the slope of mn and the slope of op are negative reciprocals.
2. y = 5x - 7.....slope here is 5....perpendicular line has a negative reciprocal slope...so the slope has to be -1/5
y= mx + b
slope(m) = -1/5
(-10,3)...x = -10 and y = 3
now we sub and find b, the y int
3 = -1/5(-10) + b
3 = 2 + b
3 - 2= b
1 = b
so ur perpendicular equation is : y = -1/5x + 1
X is a variable
6 is a constant
3 is a coefficient
