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3 years ago

12

9 Questions/45 points

1 answer:

Finger [1]3 years ago

3 0

You have a lot of questions here, try breaking them up into multiple posts and you may get more responses.

I will help with some.

<span>(x+3)=0

The solution is just -3.
-----------------------------------------------------------------
3m(m-4)=0

The two solutions are 0 and 4.
-----------------------------------------------------------------
(r-3)(r+2)=0

The two solutions are and 3 and -2.
</span>
I hope this gets you started in the right direction.

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Answer:

$x_1=\frac{3(2+i\sqrt{6})}{10}$

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Step-by-step explanation:

Use the Quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

You can identify that, in this case:

$a=-10\\b=12\\c=-9$

Now you need to substitute these values into the formula:

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Remember that:

$i=\sqrt{-1}$

Therefore,rewriting and simplifying, you get:

$x=\frac{-12\±6i\sqrt{6}}{-20}$

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$x=\frac{3(2\±i\sqrt{6})}{10}$

Then, you get the following roots:

$x_1=\frac{3(2+i\sqrt{6})}{10}$

$x_2=\frac{3(2-i\sqrt{6})}{10}$

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