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Roman55 [17]
3 years ago
10

The sum of a rational number and an irrational number

Mathematics
2 answers:
Bezzdna [24]3 years ago
6 0
The sum is irrational.
juin [17]3 years ago
4 0
Is an irrational number

Its C
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sdas [7]
I don't really know
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3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

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3 years ago
Help please i’ll give extra points
yKpoI14uk [10]

Answer:

3 units right and 1 unit up.

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Answer:

56

Step-by-step explanation:

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1. Ben had 50 baseball cards in each of 25 boxes. How many baseball cards did he have altogether?​
Romashka [77]
1,250 because there’s 25 boxes and each have 50 so you multiple 50x25 to find out how much cards are in each box
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2 years ago
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