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Roman55 [17]
3 years ago
10

The sum of a rational number and an irrational number

Mathematics
2 answers:
Bezzdna [24]3 years ago
6 0
The sum is irrational.
juin [17]3 years ago
4 0
Is an irrational number

Its C
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3. From the table below, find Prof. Xin expected value of lateness. (5 points) Lateness P(Lateness) On Time 4/5 1 Hour Late 1/10
wariber [46]

Answer:

The expected value of lateness \frac{7}{20} hours.

Step-by-step explanation:

The probability distribution of lateness is as follows:

  Lateness             P (Lateness)

  On Time                     4/5

1 Hour Late                  1/10

2 Hours Late                1/20

3 Hours Late                1/20​

The formula of expected value of a random variable is:

E(X)=\sum x\cdot P(X=x)

Compute the expected value of lateness as follows:

E(X)=\sum x\cdot P(X=x)

         =(0\times \frac{4}{5})+(1\times \frac{1}{10})+(2\times \frac{1}{20})+(3\times \frac{1}{20})\\\\=0+\frac{1}{10}+\frac{1}{10}+\frac{3}{20}\\\\=\frac{2+2+3}{20}\\\\=\frac{7}{20}

Thus, the expected value of lateness \frac{7}{20} hours.

8 0
3 years ago
Which of the following is true for an isometry?
FrozenT [24]
Isometry is defined as the <span> transformation that is invariant with respect to  the distance
The statement that is true for isometry that is corrrect is
</span><span>The preimage and the image are congruent.
</span>so correct option is A as both the preimage and image are congruent
hope it helps<span />
5 0
3 years ago
Read 2 more answers
You can make 8 pints of purple paint by mixing 6 parts of blue paint to 2 parts of red paint. The employees in the paint departm
natta225 [31]

Answer & Step-by-step explanation:

Since we use 5 parts blue and 3 parts red, the total sections is 8.

28/8 = 3.5

We want to find the red which is 3 parts.

3.5 * 3 = 10.5.

Your answer should be 10.5 pints of red.

Hope this helps!

8 0
2 years ago
PLEASE HELP<br><br> A <br> B<br> C<br> D<br> ???
Levart [38]
The answer for this would be b
4 0
3 years ago
A sample of eight workers in a clothing manufacturing company gave the following figures for the amount of time(in minutes) need
lilavasa [31]

Answer:

10.108 < \mu < 13.892    

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

We have the following distribution for the random variable:

X \sim N(\mu , \sigma=0.45)

And by the central theorem we know that the distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12

The sample deviation calculated s=2.268

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=8-1=7

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,7)".And we see that t_{\alpha/2}=2.36

Now we have everything in order to replace into formula (1):

12-2.36\frac{2.268}{\sqrt{8}}=10.108    

12+2.36\frac{2.268}{\sqrt{8}}=13.892

So on this case the 95% confidence interval would be given by (10.108;13.892)

10.108 < \mu < 13.892    

7 0
3 years ago
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