9514 1404 393
Answer:
16.8°
Step-by-step explanation:
The Law of Cosines can be rearranged to give the angle measure.
angle Q = arccos((p² +r² -q²)/(2pr))
angle Q = arccos((690² +450² -290²)/(2×690×450))
angle Q = arccos(594500/621000) ≈ 16.7985°
The measure of angle Q is about 16.8°.
To find the cofactor of
![A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%265%263%5C%5C-7%264%26-1%5C%5C-8%262%261%5Cend%7Barray%7D%5Cright%5D)
We cross out the Row and columns of the respective entries and find the determinant of the remaining 
matrix with the alternating signs.
Therefore in increasing order, we have;
The type of triangle represented in the image attached to the task content is; Isosceles.
<h3>What type of triangle is triangle ABC?</h3>
By observation; since line AB and DE are parallel lines; it follows from the alternate Angie theorem that; <ABC = <BCE = 80°.
On this note, since angle ACD is 50°, the measure on <ACB is;
180 - 80 - 50 = 50°.
Therefore, since the sum of interior angle measures in a triangle is; 180°.
It follows that; <BAC is; 180 - 80 - 50 = 50°.
Hence, since the base angles; BAC and ACB are equal; it follows that the triangle in discuss is an isosceles triangle.
Read more on isosceles triangle;
brainly.com/question/1475130
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The answer is a because i said so.
