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3 years ago

Answer please this needs to go to school tomorrow

Mathematics

1 answer:

mote1985 [20]3 years ago

4 0

5 = 29
6 = 34
7 = 39
8 = 44
9 = 49
10 = 54
11 = 59
12 = 64
13 = 69
14 = 74
15 = 79

No. Leila will not have climed 86 flights by the end of 15 weeks

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3 years ago

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sergij07 [2.7K]

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Step-by-step explanation:

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3 years ago

In triangle abc, the length of side and is 10 inches and the length of side be is 17 inches . Which of the following could be th

earnstyle [38]

Answer:

a^2=b^2+c^2.

a^2=10^2+17^2.

a^2=100+289.

a^2=389.

a=√389.

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3 years ago

The difference between two positive integers is 3. If the smaller is added to the square of the larger, the sum is 87.

Komok [63]

Let x be larger integer so x-3 is the smaller
so x^2+ x-3 = 87
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6 0

3 years ago

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

6 0

3 years ago

Read 2 more answers