Here we have a right triangle with the opposite side to the angle equal to 5.93 feet and the adjacent side to the angle equal to 12.02 feet. Therefore we just need to use the tangent definition to find the angle.

$tan(\alpha)=\frac{5.93 ft}{12.02 ft}=0.49$

$\alpha=tan^{-1}(0.49)=26.3^{\circ}$

The angle of depression of the lens must be 26.3°

I hope it helps you!

5 0

3 years ago

2 Points

ch4aika [34]

I think the answer is b

5 0

3 years ago

Help i'll mark brainliest thank you

viva [34]

Answer:

Q1: B

Q2: D

Q3: B

Q3: C

explanation:

3 0

3 years ago

Read 2 more answers

An Austrian study was completed to determine if untrained sea lions and sea lionesses could follow various experimenter-given cu

Sholpan [36]

Using the z-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.

<h3>What are the hypothesis?</h3>

At the null hypothesis, it is tested if Zwerg cannot correctly follow this type of direction by an experimenter more than 50% of the time, that is:

$H_0: p \leq 0.5$

At the alternative hypothesis, it is tested if Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time, that is:

$H_1: p > 0.5$

<h3>Test statistic</h3>

The <em>test statistic</em> is given by:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}$

In which:

$\overline{p}$ is the sample proportion.

p is the proportion tested at the null hypothesis.

n is the sample size.

For this problem, the parameters are:

$n = 48, \overline{p} = \frac{37}{48} = 0.7708, p = 0.5$

The value of the <em>test statistic</em> is:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}$

$z = \frac{0.7708 - 0.5}{\sqrt{\frac{0.5(0.5)}{48}}}$

$z = 3.75$

Considering a <u>right-tailed test</u>, as we are testing if the proportion is greater than a value, with a <u>significance level of 0.05</u>, the critical value for the z-distribution is $z^{\ast} = 1.645$ .

Since the test statistic is greater than the critical value for the right-tailed test, this result shows that Zwerg can correctly follow this type of direction by an experimenter more than 50% of the time.

To learn more about the z-distribution, you can take a look at brainly.com/question/16313918

3 0

2 years ago