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3 years ago

This will be worth ten points

Mathematics

2 answers:

Tatiana [17]3 years ago

7 0

First, you can write that 1260 ÷ 15 = 84.

To prove this one way, you can show the multiplication of the quotient and divisor. If the division was correct, it would end up as the value of the dividend:

84 * 15 = 1260
1260 = 1260

To prove this another way, you can show 84 being added 15 times and seeing if it totals 1260:

84 + 84 + 84 + 84 + 84 + 84 + 84 + 84 + 84 + 84 + 84 + 84 + 84 + 84 + 84 = 1260
1260 = 1260

vlada-n [284]3 years ago

6 0

Answer:

1260/15=84

Step-by-step explanation:

1200/15=80 and 60/15=4

80 + 4 = 84.

Another way is 15 + 15 + 15 and keep counting 84 times and you would get 84

Please mark brainliest for new rank

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Calculate f(x) for the given domain values.

Maksim231197 [3]

Answer:

See explanation

Step-by-step explanation:

1. The given function is

$f(x) = - 3x$

The domain values are: x=0, 2, -1, 4, -2

When x=0

$f(0) = - 3 \times 0 = 0$

When x=2,

$f(x) = - 3 \times 2 = - 6$

When x=-1

$f(x) = - 3 \times - 1 = 3$

When x=4

$f(4) = - 3 \times 4 = - 12$

When x=-2

$f( - 2) = - 3 \times - 2 = 6$

2. The given function is

$f(x) = \frac{1}{3} x$

When x=3,

$f(3) = \frac{1}{3} \times 3 = 1$

Similarly,

$f( - 3) = \frac{1}{3} \times - 3 = - 1$

$f(300) = \frac{1}{3} \times 300 = 100$

$f( - 180) = \frac{1}{3} \times - 180 = - 60$

$f(99) = \frac{1}{3} \times 99 = 33$

8 0

2 years ago

Consider the continuous random variable x, which has a uniform distribution over the interval from 20 to 28. refer to exhibit 6-

tatyana61 [14]

(25 -21)/(28 -20) = 4/8 = 1/2

Your probability is 1/2.

7 0

3 years ago

The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp

Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

The standard deviation of the sample is the same as the standard error of the mean. So

$SE_{M} = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\sigma = 0.35, n = 20$

$SE_{M} = \frac{\sigma}{\sqrt{n}}$

$SE_{M} = \frac{0.35}{\sqrt{20}}$

$SE_{M} = 0.0783$

The standard error of the mean is 0.0783.

7 0

3 years ago

Someone help !!!<br> ill do anything i promise

prisoha [69]

Answer:

1/600, 6/100, 1/1400

Step-by-step explanation:

4 0

3 years ago

BRAINLIEST<br>Find the value of x in each of the following exercises:

ohaa [14]

The value of x is 120°

Explanation:

It is given that ABC is a straight line.

Also, ∠CBE = 20° and ∠CAF = 40°

We need to determine the value of ∠DBE

Let ∠DBE = x

Since, ∠CAF and ∠ABD are alternate interior angles.

By the alternate interior angles theorem, "if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are equal".

Thus, ∠CAF and ∠ABD are equal.

Hence, ∠CAF = ∠ABD = 40°

Since, we know that, the angles in a straight line add up to 180°, we have,

∠ABD + ∠DBE + ∠CBE = 180°

Substituting the values, we get,

40° + x + 20° = 180°

Adding, we have,

60° + x = 180°

Subtracting both sides by 60, we have,

x = 120°

Thus, the value of x is 120°

5 0

3 years ago