Consider f(x) = -4(x - 6)² + 3 This is a parabola with vertex at (6, 3). Because the leading coefficient of -4 is negative, the curve opens downward, and the vertex is the maximum value.
Answer: Maximum of f(X) = 3
Consider the function g(x) = 2 cos(2x - π) + 4 The maximum value of the cosine function is 1. Therefore the maximum value of g(x) is 2*1 + 4 = 6
