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egoroff_w [7]
2 years ago
7

If i'm in 9th grade right now what years was my 6th grade year ?

Mathematics
1 answer:
creativ13 [48]2 years ago
5 0

Answer:

2017-2018

Step-by-step explanation:

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18x^2

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You're basically just multiplying them together :)

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The answer should be B. 86.7

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-3 x^2 + 10x + 7

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PLEASE HELP.!! THANK YOUU. accurate answers appreciated:)
Anni [7]

\bf \cfrac{1}{1-sin(x)}+\cfrac{1}{1+sin(x)}=\cfrac{2}{cos^2(x)} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the LCD of [1-sin(x)][1+sin(x)]}}{\cfrac{[1+sin(x)]1~~+~~[1-sin(x)]1}{\underset{\textit{difference of squares}}{[1-sin(x)][1+sin(x)]}}} \\\\\\ \cfrac{1+sin(x)+1-sin(x)}{1^2-sin^2(x)}\implies \cfrac{1+sin(x)+1-sin(x)}{1-sin^2(x)}

recall that 1 - sin²(θ) = cos²(θ).

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