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Komok [63]
3 years ago
8

The amount of time necessary for assembly line workers to complete a product is a normal variable with a mean of 15 minutes and

a standard deviation of 2 minutes. the probability is ________ that a product is assembled in less than 12 minutes

Mathematics
1 answer:
Sliva [168]3 years ago
4 0
The probability is 0.0668 that a product is assembled in less than 12 minutes.

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Bonita said that the product of 5/6× 1 2/3 is 7/3.<br> How can you tell that her answer is wrong?
Olin [163]

\frac{5}{6}  \times 1 \frac{2}{3}  \\ \\   = \frac{5}{6}  \times  \frac{1 \times 3 + 2}{3}   \\ \\  = \frac{5}{6}  \times  \frac{5}{3}  \\  \\  =  \frac{25}{18}

The correct answer is 25/18.

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Answer:

b

Step-by-step explanation:

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2 years ago
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Marizza181 [45]
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336569.04
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5 0
4 years ago
Read 2 more answers
The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the v
Svetllana [295]

Answer:

The differential equation becomes -

\frac{dV}{dt} = k\sqrt[3]{V} i.e. \frac{dV}{dt} = kV^{\frac{1}{3} }

Step-by-step explanation:

Given - The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

To find - Write a differential equation that describes the relationship.

Proof -

Rate of change of volume V with respect to time t is represented by \frac{dV}{dt}

Now,

Given that,

The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

⇒\frac{dV}{dt} ∝ \sqrt[3]{V}

Now,

We know that, when we have to remove the Proportionality sign , we just put a constant sign.

Let k be any constant.

So,

The differential equation becomes -

\frac{dV}{dt} = k\sqrt[3]{V} i.e. \frac{dV}{dt} = kV^{\frac{1}{3} }

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3 years ago
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Second answer: f - 52 = 63.
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