Answer:
The average rate of change of the given function
A(x) = 1
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given function f(x) = x² - 2x -4
And given that x = a = -1 and x=b = 4
The average rate of change of the given function

<u><em>Step(ii):-</em></u>
f(x) = x² - 2x -4
f(-1) = (-1)² - 2(-1) -4 = 1+2-4 = -1
f(4) = 4² -2(4) -4 = 16 -12 = 4
The average rate of change of the given function


<u><em>final answer:-</em></u>
The average rate of change of the given function
A(x) = 1
Answer:
x=4
Step-by-step explanation:
To solve for x, use inverse operations:
-8x+3 = -29 Subtract 3 from both sides
-8x +3 -3 = -29 -3
-8x = -32 Divide both sides by -8
x = 4
Answer:
Bc=20
Step-by-step explanation:
Sin61=BC/AC=BC/23
BC=23sin61=20
Answer:
If you mean 2 and 3 it would be (x-2)(x-3)=0
Step-by-step explanation:
(x-2)=0
x-2=0 move the two on the other side to get positive
x=2
(x-3)=0
x-3=0 move the three on the other side to get positive
x=3
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Let


because that is the range of the inverse cosine funcition.
Also,
![\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\ \mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}](https://tex.z-dn.net/?f=%5Cmathsf%7Bcos%5C%2C%5Ctheta%3Dcos%5C%21%5Cleft%5Bcos%5E%7B-1%7D%5C%21%5Cleft%28%5Cdfrac%7B4%7D%7B5%7D%5Cright%29%5Cright%5D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7Bcos%5C%2C%5Ctheta%3D%5Cdfrac%7B4%7D%7B5%7D%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7B5%5C%2Ccos%5C%2C%5Ctheta%3D4%7D)
Square both sides and apply the fundamental trigonometric identity:



But

which means

lies either in the 1st or the 2nd quadrant. So

is a positive number:
![\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\ \therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}](https://tex.z-dn.net/?f=%5Cmathsf%7Bsin%5C%2C%5Ctheta%3D%5Cdfrac%7B3%7D%7B5%7D%7D%5C%5C%5C%5C%5C%5C%0A%5Ctherefore~~%5Cmathsf%7Bsin%5C%21%5Cleft%5Bcos%5E%7B-1%7D%5C%21%5Cleft%28%5Cdfrac%7B4%7D%7B5%7D%5Cright%29%5Cright%5D%3D%5Cdfrac%7B3%7D%7B5%7D%5Cqquad%5Cquad%5Ccheckmark%7D)
I hope this helps. =)
Tags: <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>