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3 years ago

Bonita said that the product of 5/6× 1 2/3 is 7/3. How can you tell that her answer is wrong?

1 answer:

5 0

$\frac{5}{6} \times 1 \frac{2}{3} \\ \\ = \frac{5}{6} \times \frac{1 \times 3 + 2}{3} \\ \\ = \frac{5}{6} \times \frac{5}{3} \\ \\ = \frac{25}{18}$

The correct answer is 25/18.

her answer is wrong

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Let e f (x) = x2 – 2x - 4 What is the average rate of change for the quadratic function from X = -1 tox to x = 42 Enter your ans

sammy [17]

Answer:

The average rate of change of the given function

A(x) = 1

Step-by-step explanation:

Step(i):-

Given function f(x) = x² - 2x -4

And given that x = a = -1 and x=b = 4

The average rate of change of the given function

$A(x) = \frac{f(b)-f(a)}{b-a}$

Step(ii):-

f(x) = x² - 2x -4

f(-1) = (-1)² - 2(-1) -4 = 1+2-4 = -1

f(4) = 4² -2(4) -4 = 16 -12 = 4

The average rate of change of the given function

$A(x) = \frac{f(b)-f(a)}{b-a}$

$A(x) = \frac{4-(-1)}{4-(-1)} = \frac{5}{5} = 1$

final answer:-

The average rate of change of the given function

A(x) = 1

5 0

3 years ago

Read 2 more answers

-8 x+3=-29 what is x?

kykrilka [37]

Answer:

x=4

Step-by-step explanation:

To solve for x, use inverse operations:

-8x+3 = -29 Subtract 3 from both sides

-8x +3 -3 = -29 -3

-8x = -32 Divide both sides by -8

x = 4

3 0

3 years ago

Law of Sine.

kykrilka [37]

Answer:

Bc=20

Step-by-step explanation:

Sin61=BC/AC=BC/23

BC=23sin61=20

4 0

3 years ago

Which equation has the solution set x = (23) ?

Svet_ta [14]

Answer:

If you mean 2 and 3 it would be (x-2)(x-3)=0

Step-by-step explanation:

(x-2)=0

x-2=0 move the two on the other side to get positive

x=2

(x-3)=0

x-3=0 move the three on the other side to get positive

x=3

4 0

3 years ago

Find the exact value of sin(cos^-1(4/5))

boyakko [2]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2762144

_______________

Let $\mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}$

$\mathsf{0\le \theta\le\pi,}$ because that is the range of the inverse cosine funcition.

Also,

$\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}$

Square both sides and apply the fundamental trigonometric identity:

$\mathsf{(5\,cos\,\theta)^2=4^2}\\\\
\mathsf{5^2\,cos^2\,\theta=4^2}\\\\
\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{25\cdot (1-sin^2\,\theta)=16}$

$\mathsf{25-25\,sin^2\,\theta=16}\\\\
\mathsf{25-16=25\,sin^2\,\theta}\\\\
\mathsf{9=25\,sin^2\,\theta}\\\\
\mathsf{sin^2\,\theta=\dfrac{9}{25}}
$

$\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}$

But $\mathsf{0\le \theta\le\pi,}$ which means $\theta$ lies either in the 1st or the 2nd quadrant. So $\mathsf{sin\,\theta}$ is a positive number:

$\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\
\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: inverse trigonometric function cosine sine cos sin trig trigonometry

3 0

3 years ago

Read 2 more answers