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skelet666 [1.2K]
3 years ago
10

Bonita said that the product of 5/6× 1 2/3 is 7/3. How can you tell that her answer is wrong?

Mathematics
1 answer:
Olin [163]3 years ago
5 0

\frac{5}{6}  \times 1 \frac{2}{3}  \\ \\   = \frac{5}{6}  \times  \frac{1 \times 3 + 2}{3}   \\ \\  = \frac{5}{6}  \times  \frac{5}{3}  \\  \\  =  \frac{25}{18}

The correct answer is 25/18.

her answer is wrong
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Let e f (x) = x2 – 2x - 4 What is the average rate of change for the quadratic function from X = -1 tox to x = 42 Enter your ans
sammy [17]

Answer:

The average rate of change of the given function

A(x) =  1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function f(x) = x² - 2x -4

And given that x = a = -1 and  x=b = 4

The average rate of change of the given function

A(x) = \frac{f(b)-f(a)}{b-a}

<u><em>Step(ii):-</em></u>

f(x) = x² - 2x -4

f(-1) = (-1)² - 2(-1) -4 = 1+2-4 = -1

f(4) = 4² -2(4) -4 = 16 -12 = 4

The average rate of change of the given function

A(x) = \frac{f(b)-f(a)}{b-a}

A(x) = \frac{4-(-1)}{4-(-1)} = \frac{5}{5} = 1

<u><em>final answer:-</em></u>

The average rate of change of the given function

A(x) =  1

5 0
3 years ago
Read 2 more answers
-8 x+3=-29 what is x?
kykrilka [37]

Answer:

x=4

Step-by-step explanation:

To solve for x, use inverse operations:

-8x+3 = -29               Subtract 3 from both sides

-8x +3 -3 = -29 -3

-8x = -32                    Divide both sides by -8

x = 4

3 0
3 years ago
Law of Sine.
kykrilka [37]

Answer:

Bc=20

Step-by-step explanation:

Sin61=BC/AC=BC/23

BC=23sin61=20

4 0
3 years ago
Which equation has the solution set x = (23) ?
Svet_ta [14]

Answer:

If you mean 2 and 3 it would be (x-2)(x-3)=0

Step-by-step explanation:

(x-2)=0

x-2=0 move the two on the other side to get positive

x=2

(x-3)=0

x-3=0 move the three on the other side to get positive

x=3

4 0
3 years ago
Find the exact value of sin(cos^-1(4/5))
boyakko [2]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2762144

_______________


Let  \mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}


\mathsf{0\le \theta\le\pi,}  because that is the range of the inverse cosine funcition.


Also,

\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\&#10;\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}


Square both sides and apply the fundamental trigonometric identity:

\mathsf{(5\,cos\,\theta)^2=4^2}\\\\&#10;\mathsf{5^2\,cos^2\,\theta=4^2}\\\\&#10;\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\&#10;\mathsf{25\cdot (1-sin^2\,\theta)=16}

\mathsf{25-25\,sin^2\,\theta=16}\\\\&#10;\mathsf{25-16=25\,sin^2\,\theta}\\\\&#10;\mathsf{9=25\,sin^2\,\theta}\\\\&#10;\mathsf{sin^2\,\theta=\dfrac{9}{25}}&#10;

\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}


But \mathsf{0\le \theta\le\pi,} which means \theta lies either in the 1st or the 2nd quadrant. So \mathsf{sin\,\theta} is a positive number:

\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\&#10;\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

3 0
3 years ago
Read 2 more answers
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