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Ymorist [56]
3 years ago
12

Write out how you found the answer.

Mathematics
2 answers:
ollegr [7]3 years ago
4 0

Step-by-step explanation:

DC = DF + FE + EC = 3 + 14 +6 = 23 in (\because FE = AB)

Area of trapezoid ABCD

=  \frac{1}{2} (AB + CD) \times BE \\  \\  = \frac{1}{2} (14 + 23) \times 8 \\  \\  = 37 \times 4 \\  \\  = 148 \:  {in}^{2}

Lady bird [3.3K]3 years ago
4 0

Answer:184 in²

Step-by-step explanation:

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Solve the inequality 6.2n < 2n + 8.4​
Degger [83]

Answer:

n<2

Step-by-step explanation:

6.2n<2n+8.4

Move variable to the left hand side and change its sign

6.2n - 2n < 8.4

Combine like terms

4.2n < 8.4

divide both side by 4.2

n < 2

6 0
3 years ago
Determine whether the following relation is a function. {(-6, – 8), (5, 1). (9.-4), (7,2), (15, 0)} ​
lidiya [134]

This relation is a function. None of the x-values repeat. Each y-value belongs to a specific x-value.

4 0
3 years ago
A person is standing 200ft from a tower. She can see the top of the tower at a 42 degree angle of elevation. Her eyes are 5ft ab
Oxana [17]

Answer:

C. 185 ft

Step-by-step explanation:

The work is in the attached picture file, if you need it. Basically the question sets up a right triangle, for which the base is 200 and the height is the goal that you are solving for. It is given that the angle between hypotenuse and base is 42 degrees. For this you use tangent to say that

         tan(42) = h / 200

         200 tan (42) = h

         h = 180 feet.

But then you must remember that this triangle starts 5 feet off of the ground. So you add the 5 feet and get 185 feet as the height of the tower.

6 0
3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
Elodia [21]

Answer:

7.3% percentage of the bearings produced will not be acceptable.

Step-by-step explanation:

Consider the provided information.

Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.

Let X is the normal random variable which represents the diameter of bearing.

Thus, 0.500-0.004<X<0.500+0.004

0.496<X<0.504

The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.

Use the Z score formula: \frac{X-\mu}{\sigma}

Therefore

\frac{0.496-0.499}{0.002}\leq z\leq \frac{0.504-0.499}{0.002}

\frac{-0.003}{0.002}\leq z\leq \frac{0.005}{0.002}

-1.5\leq z\leq 2.5

Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.

P(-1.5\leq z\leq 2.5)=0.9938-0.0668=0.9270

We need to find the percentage of the bearings produced will not be acceptable.

So subtract it from 1 as shown.

1-0.9270=0.073

Hence, 7.3% percentage of the bearings produced will not be acceptable.

3 0
3 years ago
Simplify (3x2 + 2x + 7x3) + (10x2 + 6x + 9)
torisob [31]
I hope this helps you 3x^2+2x+7x^3+10x^2+6x+9 7x^3+13x^2+8x+9
4 0
3 years ago
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