Answer:
d. 944 mm^3
Step-by-step explanation:
The area of a circle is given by ...
A = πr² . . . . . where r is the radius, half the diameter
The area of a circle with diameter 9 mm is ...
A = π(4.5 mm)² = 20.25π mm²
The area of the semi-circular end of the prism is half this value, or ...
semicircle area = (1/2)(20.25π mm²) = 10.125π mm² ≈ 31.809 mm²
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The area of the rectangular portion of the end of the prism is the product of its width and height:
A = wh = (9 mm)(6 mm) = 54 mm²
Then the base area of the prism is ...
base area = rectangle area + semicircle area
= (54 mm²) +(31.809 mm²) = 85.809 mm²
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This base area multiplied by the 11 mm length of the prism gives its volume:
V = Bh = (85.809 mm²)(11 mm) ≈ 944 mm³
The volume of the composite figure is about 944 mm³.
Step-by-step explanation:
1)ab-c
=2(3)-4
=6-4
=2
2)6c-2b
=6(4)-2(3)
=24-6
=18
3)a+b-c+5
=2+3-4+5
=10-4
=6
5)7c-2a
=7(4)-2(2)
=28-4
=24
Well it depends on what the model is but if it's an IRA or whatever so if you make your own model that's easy
The system should look like this:
eh + b = 243
eh - b = 109
