3 years ago

Find three consecutive odd numbers whose sum is 303

2 answers:

8 0

$n;\ n+2;\ n+4-three\ consecutive\ odd\ numbers\\\\n+(n+2)+(n+4)=303\\\\3n+6=303\\\\3n=303-6\\\\3n=297\ \ \ \ /:3\\\\n=99\\\\Answer:99;\ 101;\ 103.$

Roman55 [17]3 years ago

5 0

99 + 101 + 103 = 303

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