Question

Find three consecutive odd numbers whose sum is 303

Answer 1

$n;\ n+2;\ n+4-three\ consecutive\ odd\ numbers\\\\n+(n+2)+(n+4)=303\\\\3n+6=303\\\\3n=303-6\\\\3n=297\ \ \ \ /:3\\\\n=99\\\\Answer:99;\ 101;\ 103.$

Answer 2

99 + 101 + 103 = 303