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NeTakaya
3 years ago
12

John’s bank account increased in value from last year to those year by 8% to $250. If the account increases by the same percenta

ge over the next year, what will be the value next year?
Mathematics
1 answer:
inessss [21]3 years ago
4 0

Answer:

$270

Step-by-step explanation:

We are given;

  • The rate of increase is 8%
  • The new amount is $250

We need to determine the value in the next year with the same rate of increase;

Therefore;

250% = 100%

New amount = 100 + 8 = 108%

Therefore;

New amount = (250 × 108)÷ 100

                      = $270

Therefore, the value in the next year is $270

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the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
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<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

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Which of the following is a trinomial with a constant term?
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is A

Step-by-step explanation:

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