I believe (7.5, 12.5) is the answer. The answer is where both lines intersect unless there is more to the question.
Answer:
Therefore the diameter of the hole is m.
Step-by-step explanation:
Bernoulli's equation,
P₁ = P₂= atmospheric presser
= density
[since P₁ = P₂]
[]
Here
Here g= 9.8 m/s² , h = 10.4 m
The velocity of water that leaves from the hole = m/s
=14.28 m/s.
Given, the rate of flow from the leak is
Let the diameter of the hole be d.
Then the cross section area of the hole is
We know that,
The rate of flow = Cross section area × speed
Therefore the diameter of the hole is m.
Does a picture go along with this?
I believe the answer is D
F(2)=-3f(2-1)-2f(2-2)
=-3f(1)-2(0)
=-3*12-2*-4
=-36+8
=-28
we have f0,f1,f2,f3 is last
we know -4,12,-28, i leave it to u to find f(3)
plug in n=3 and solve