All categories

3 years ago

Pls help it due ASAP and show workings

Mathematics

1 answer:

Effectus [21]3 years ago

7 0

Answer:

it's 70°

Step-by-step explanation:

well first by vertical angles we know that

$\angle BAC = \angle DAE\\\\\angle DAE = 4x+6$ ( I don't know how to put the symbol xd)

and given we know that

$\angle EAF = \angle EAD = 4x+6$

solving for x

we know that

$\angle CAD = 180\\\\\angle CAB + \angle ABD = 180\\\\4x+6+6x+14=180\\\\10x+20=180\\\\10x=160\\\\x=16$

and now for $\angle EAF$

$\angle EAF = 4x+6\\\\\angle EAF = 4(16)+6\\\\\angle EAF = 64+6\\\\\angle EAF = 70$

You might be interested in

What is the value of x? Enter your answer in the box. °

Gnom [1K]

Answer:

The answer to your question is: 111°

Step-by-step explanation:

The sum of the interior angles of a polygon is (n - 2) 180°

This polygon has 7 sides

Then n = 7

Process

120 + 158 + 126 + 125 + 121 + 139 + x = (7 - 2)180

120 + 158 + 126 + 125 + 121 + 139 + x = 5(180)

789 + x = 900

x = 900 -789

x = 111°

5 0

3 years ago

Suppose JK bisects angle LJM. The measure of angle LJK = (-10x + 3) and the measure of KJM = (-x + 21)º. Find the measure of ang

SpyIntel [72]

LJK = KJM -10x +3 = -x + 21 -10x + x = 21 - 3 -9x = 18 x = -2 KJM = -x + 21 = 2 + 21 = 23 LJM = LJK + KJM LJM = 23 + 23 LJM = 46º..

i think thats how its done

7 0

3 years ago

5x^{2}-44x+120=-30+11x i am confuseddddd

Luba_88 [7]

Answer: x=6 x=5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If a die is rolled one time, find probability of getting a number greater than 3 and an odd number.

Nadya [2.5K]

Answer:

$\dfrac{1}{6}$ .

Step-by-step explanation:

It is given that a die is rolled one time. So,

Sample space : $S=\{1,2,3,4,5,6\}$

Number is greater than 3 : $A=\{4,5,6\}$

Number is odd : $A=\{1,3,5\}$

Number greater than 3 and an odd number : $A\cap B=\{5\}$

It is conclude that,

$n(S)=6, n(A)=3,n(B)=3,n(A\cap B)=1$

The probability of getting a number greater than 3 and an odd number is

$P=\dfrac{n(A\cap B)}{n(S)}$

$P=\dfrac{1}{6}$

Therefore, the required probability is $\dfrac{1}{6}$ .

4 0

3 years ago

Twenty-five randomly selected students were asked the number of movies they watched the previous week. The results are as follow

guajiro [1.7K]

Answer:

a) x = 1.52

b) s = 1.16

Step-by-step explanation:

We have that:

5 students watched 0 movies.

9 students watched 1 movie.

5 students watched 2 movies.

5 students watched 3 movies.

1 student watched 4 movies.

(a) Find the sample mean x.

Sum divided by the number of students. So

$x = \frac{5*0 + 9*1 + 5*2 + 5*3 + 1*4}{5 + 9 + 5 + 5 + 1} = \frac{38}{25} = 1.52$

(b) Find the approximate sample standard deviation, s.

Standard deviation of the sample.

Square root of the sum of the squares of the values subtracted from the mean, divided by the sample size subtracted by 1. So

$s = \sqrt{\frac{5*(0-1.52)^2 + 9*(1-1.52)^2 + 5*(2-1.52)^2 + 5*(3-1.52)^2 + 1*(4-1.52)^2}{24}} = \sqrt{\frac{32.24}{24}} = 1.16$

3 0

3 years ago