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Inga [223]
3 years ago
9

Which property applies only to addition and multiplication

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0
*Commutativity*, which basically says that order does matter.

2 + 1 is the same as 1 + 2, and 3 x 4 is the same as 4 x 3.
prohojiy [21]3 years ago
5 0
The communitive(i honestly don't know how to spell it) property works for addition and multiplication, when you switch the numbers around the equal the same. Unlike when you switch the numbers around in division or subtraction you will get a completely different answer if it was vise versa.
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A theater sells two types of tickets to their plays, children's tickets and adult tickets. For today's persformance they have so
evablogger [386]
784 adult tickets
Adult + children’s tickets = 1488
(1488-80)/2+80= adult tickets
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3 years ago
Which represents the RANGE of the following relation? {(-6, 5), (-4, 3), (-1, 0), (4, 3)} A (5, 3, 0, 3) B (-6, 4, 1, -4) C (0,
nikklg [1K]

Answer:

Domain:

{ − 6 , − 4 , − 1 }

Range:

{ 5 , 3 , 0 }

Step-by-step explanation:

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3 years ago
Find the value of X in the picture
Alja [10]

Answer:

Step-by-step explanation:188

6 0
3 years ago
Read 2 more answers
7 x n =42+7<br><br> A. 6<br> B.7<br> C.42<br> D.56<br> E.294
Darina [25.2K]
THE ANSWER IS B CAUSE 7X7=49 AS WELL
3 0
3 years ago
Read 2 more answers
) Thirty percent of the students in a management class are graduate students. A random sample of 3 students is selected. a) Usin
adell [148]

Given Information:  

Probability of success = 30%

Sample size = n = 3

Variable of interest = x = 2  

Required Information:  

Probability of exactly 2 graduates = ?

Answer:

Probability of exactly 2 graduates = P(2; 3, 0.30) = 0.189

Step-by-step explanation:

The given problem can be modeled as a binomial experiment since a random selected student can either b graduate or not therefore, there are only 2 outcomes. Each trial is independent and the probability of success is not changing from trial to trial. The number of trials in also fixed.

We know that a binomial distribution is given by

P(x; n, p) = nCx pˣ (1 - p)ⁿ⁻ˣ

Where p is the probability of success and 1 - p is the probability of failure, n is number of independent trials and x is the variable of interest.

For the given problem, we know that x = 2, n = 3 and p = 0.30

P(2; 3, 0.30) = 3C2*0.30²*(1 - 0.30)³⁻²

P(2; 3, 0.30) = 3*0.30²*(0.70)¹

P(2; 3, 0.30) = 0.189

3 0
4 years ago
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