Bruce has a rope that is 21 feet long he needs to cut the rope into 1/5 long pieces.
The length of the rope = 21 feet
the length of each strip =
We need to cut the rope 21 feet into strips
To find the number of strips we divide 21 feet by the length of the strip
=
= 105
105 strips can Bruce cut from his rope.
Answer:
(a) The correct answer is P (CBM) = 0.79.
(b) The probability of selecting an American female who is not red-green color-blind is 0.996.
(c) The probability that neither are red-green color-blind is 0.9263.
(d) The probability that at least one of them is red-green color-blind is 0.0737.
Step-by-step explanation:
The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.
It is provided that 79% of men and 0.4% of women are colorblind, i.e.
P (CBM) = 0.79
P (CBW) = 0.004
(a)
The probability of selecting an American male who is red-green color-blind is, 0.79.
Thus, the correct answer is P (CBM) = 0.79.
(b)
The probability of the complement of an event is the probability of that event not happening.
Then,
P(not CBW) = 1 - P(CBW)
= 1 - 0.004
= 0.996.
Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.
(c)
The probability the woman is not colorblind is 0.996.
The probability that the man is not color- blind is,
P(not CBM) = 1 - P(CBM)
= 1 - 0.004
= 0.93.
The man and woman are selected independently.
Compute the probability that neither are red-green color-blind as follows:
Thus, the probability that neither are red-green color-blind is 0.9263.
(d)
It is provided that a one man and one woman are selected at random.
The event that “At least one is colorblind” is the complement of part (d) that “Neither is Colorblind.”
Compute the probability that at least one of them is red-green color-blind as follows:
Thus, the probability that at least one of them is red-green color-blind is 0.0737.