the horizontal distance between the child and the crackers is 2.9 ft .
<u>Step-by-step explanation:</u>
Here we have , A child spots crackers in a cabinet at an angle of elevation of 50. The crackers are 3.5 ft above the child. We need to find what is the horizontal distance between the child and the crackers . Let's find out:
According to question , we have a right angle triangle with parameters as :
, Where x is angle of elevation !
We know that , 
⇒
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the horizontal distance between the child and the crackers is 2.9 ft .
Answer:
Step-by-step explanation:
The area for a parallelogram is given by the formula:
Where b is the base length and h is the vertical height.
The base length is 16.9 while the vertical height is 8.7. Thus:
Multiply using a calculator:
Answer:1
Step-by-step explanation:
6/20+14/20=
20/20
=1
The answer of this question is 152
y=-x
slope for perp line = 1
2y=-x+6
y=-1/2x +3
slope for perp line = 2
15.
i don’t wanna do all sorry it’s a lot of work so i’ll tell u how to do it instead. first write it in slope intercept form which is
y-y1=m(x-x1)
it’s parallel which means it shares the same slope. if it’s perpendicular it would be opposite reciprocals so for -3/2 the perp slope would be 2/3.
the line is
y+1=3/4(x-4)
we distribute the 3/4 so it’s now
y+1=3/4x-3
then we subtract the 1
y=3/4x-4 is the equation boom done
