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saw5 [17]
3 years ago
8

The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability d

istribution: On average, how many accidents are there in the intersection in a week
Mathematics
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

Average Mean = 1.8

Step-by-step explanation:

Missing:

X:0 1 2 3 4 5 6

P(x): 0.20 0.30 0.20 0.15 0.10 0.05

Computation:

Average Mean [Probability distribution]

∑[P(x) × X]

= 0 x 0.20 + 1 x 0.30 + 2 x 0.20 + 3 x 0.15 + 4 x 0.10 + 5 x 0.05

= 1.8

Average Mean = 1.8

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Question 8 of 10
Andreyy89

Median and IQR are the most appropriate measures of center and spread for this data set.

<h3>Why are Median and IQR the most appropriate?</h3>

Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:

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