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Kazeer [188]
3 years ago
5

Can someone check if I this is right?

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0
Yes it looks correct. The slope and y intercept match, visually.
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Jake gave the cashier $50 to pay for 5 pairs of jeans. The cashier gave him
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Answer:

8.85

Step-by-step explanation:

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A media poll of 500 air travelers surveyed in national airports found that 370 favor tighter security procedures in boarding pla
serg [7]

Answer:

92% Confidence interval:  (0.7078,0.7722)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 500

Number of travelers who favor tight security, x = 370

\hat{p} = \dfrac{x}{n} = \dfrac{370}{500} = 0.74

92% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.08} = \pm 1.645

Putting the values, we get:

0.74\pm 1.645(\sqrt{\dfrac{0.74(1-0.74)}{500}}) = 0.74\pm 0.0322\\\\=(0.7078,0.7722)

3 0
3 years ago
(40 POINTS!!) solve for x
aev [14]

Answer:

do 13+7 you will have your answer. (go down for answer)

Step-by-step explanation:

its 20

4 0
3 years ago
GEOMETRY! Please help!
tatiyna

Answer: perimeter = 62

Step-by-step explanation:

To determine the length of the unknown sides of the triangle, we would apply the sine rule which is expressed as

a/SinA = b/SinB = c/SinC

Therefore

AB/Sin 40 = 19.5/Sin 49

ABSin49 = 19.5Sin40 = 19.5 × 0.64

0.755AB = 12.48

AB = 12.48/0.755

AB = 16.5

The sum of the angles in a triangle is 180°. Therefore,

A = 180 - (40 + 49) = 91°

BC/Sin 91 = 19.5/Sin 49

BCSin49 = 19.5Sin91 = 19.5 × 0.9998

0.755BC = 19.5

BC = 19.5/0.755

BC = 25.8

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = a + b + c

Where

a, b and c represents the length of each side of the triangle.

Perimeter of triangle = 25.8 + 16.5 + 19.5 = 62

6 0
3 years ago
Calculate the sample variance and sample standard deviation for the following frequency distribution of heights in centimeters f
Wittaler [7]

Answer:

s^2 = 0.9938 --- sample variance

s = 0.9969 --- sample standard deviation

Step-by-step explanation:

Given

\begin{array}{cc}{Heights} & {Frequency} & {116.1-120.0} & {38} & {120.1-124.0} & {24} &{124.1-128.0} & {28} & {128.1-132.0} & {43} & {132.1-136.0} & {29} \ \end{array}

Required

Calculate the sample variance and sample standard deviation

First, we calculate the midpoint of each class:

\begin{array}{ccc}{Heights} & {Frequency} & {m} &{116.1-120.0} & {38} & {118.05}& {120.1-124.0} & {24}& {122.05} &{124.1-128.0} & {28} &{126.05}& {128.1-132.0} & {43} & {130.05} &{132.1-136.0} & {29} &{134.05}\ \end{array}

The midpoints are calculated by taking the average of the class intervals.

For instance:

Class 116.1 to 120.0 has a midpoint of

m = \frac{1}{2}(116.1+120.0)

m = \frac{1}{2}(236.1)

m = 118.05

The same approach is applied to other classes.

Next, is to calculate the mean:

\bar x = \frac{\sum fx}{\sum f}

In this case, it is:

\bar x = \frac{\sum fm}{\sum f}

Where

m = midpoint

So, we have:

\bar x = \frac{118.05*38+122.05*24+126.05*28+130.05*43+134.05*29}{38+24+28+43+29}

\bar x = \frac{20424.10}{162}

\bar x = 126.07

The sample variance (s^2) is:

s^2 = \frac{\sum(m - \bar x)^2}{\sum f -1}

This gives:

s^2 = \frac{(118.05-126.07)^2+(122.05-126.07)^2+(126.05-126.07)^2+(130.05-126.07)^2+(134.05-126.07)^2}{38+24+28+43+29-1}

s^2 = \frac{160.002}{161}

s^2 = 0.9938

The sample standard deviation (s) is:

s = \sqrt{s^2

s = \sqrt{0.9938

s = 0.9969

5 0
3 years ago
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