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aliina [53]
3 years ago
11

The figure shows three quadrilaterals on a coordinate grid:

Mathematics
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

W and Q are similar and congruent.

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3208 rounded to the nearest ten place
algol13
3210 is the answer
8 is closer to 10 then 5 is closer to 0
4 0
3 years ago
Read 2 more answers
Please help me solve question 2
sergiy2304 [10]

Answer:

solution: ( 3 , 6 )

\sf y =6

\sf x =3

Step-by-step explanation:

\sf y = \frac{2}{3} x+4

\sf 2x+3y = 24

make y the subject in equation 2:

\sf 2x+3y = 24

\sf 3y = 24-2x

\sf y = \frac{24-2x}{3}

insert this in equation 1:

\sf \frac{24-2x}{3} =\frac{2}{3} x+4

\sf \sf \frac{24-2x}{3} =\frac{2x+12}{3}

\sf (24-2x) = (2x+12)

\sf -2x-2x=12-24

\sf -4x=-12

\sf x =3

solve for y:

\sf y = \frac{24-2x}{3}

\sf y = \frac{24-2(3)}{3}

\sf y =6

8 0
2 years ago
Read 2 more answers
What is 5.95 × 106 written in standard form? A. 595,000 B. 59,500 C. 5950 D. 5,950,000
tiny-mole [99]
The answer is option D "<span>5,950,000".

</span>5.95 * 10^6 = &#10;&#10;5 9 5 0 0 0 0/&#10;1 2 3 4 5 6

Which would equal 5,950,000.

Hope this helps!
7 0
3 years ago
The distribution of prices for home sales in a certain New Jersey county is skewed to the right with a mean of $290,000 and a st
I am Lyosha [343]

Answer:

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413) = 0.008

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given the mean of the Population( )= $290,000

Standard deviation of the Population = $145,000

Given the size of the sample 'n' = 100

Given 'X⁻'  be a random variable in Normal distribution

Let   X⁻ = 325,000

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }  = \frac{325000-290000}{\frac{145000}{\sqrt{100} } }  = 2.413

<u><em>Step(ii):</em></u>-

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413)

                           = 0.5 - A(2.413)

                           = 0.5 - 0.4920

                           = 0.008

<u><em>Final answer:-</em></u>

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413) = 0.008

6 0
2 years ago
Can somone explain to me how to do this and help me thansk!!!
Gnesinka [82]
=> x² = (2.4)² + (4.8)²

=> x² = 5.76 + 23.04

=> x² = 28.8

=> x = 5.366563146

=> x = 5.4

Ans: 2nd option (5.4)

Hope this helps!
6 0
2 years ago
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