9514 1404 393
Answer:
$4127
Step-by-step explanation:
The amortization formula is good for finding this value.
A = P(r/12)/(1 -(1 +r/12)^(-12t))
where P is the amount invested at rate r for t years.
A = $600,000(0.055/12)/(1 -(1 +0.055/12)^(-12·20)) = $4127.32
You will be able to withdraw $4127 monthly for 20 years.
Answer:
x+14
Step-by-step explanation:
(12+x)+2
12+x+2
x+(12+2)
x+14
Answer:
61,940
Step-by-step explanation:
For a recursive sequence of reasonable length, it is convenient to use a suitable calculator for figuring the terms of it. Since each term not only depends on previous terms, but also depends on the term number, it works well to use a spreadsheet for doing the calculations. The formula is easily entered and replicated for as many terms as may be required.
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The result of executing the given algorithm is shown in the attachment. (We have assumed that g_1 means g[-1], and that g_2 means g[-2]. These are the starting values required to compute g[0] when k=0.
That calculation looks like ...
g[0] = (0 -1)×g[-1] +g[-2} = (-1)(9) +5 = -4
The attachment shows the last term (for k=8) is 61,940.
Answer:
A). 
B). 
Step-by-step explanation:
A). 
To get the square root of the given expression we will convert it into the square form.
[Since 2×2 = 4 and
]
Therefore, 

B). 
Since, 
Therefore,
[Since 3² = 9 and (m⁷)² = m¹⁴]