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3 years ago

Sam is 5 years older than Michelle. If Michelle is m years old, write an

Mathematics

1 answer:

Airida [17]3 years ago

8 0

Answer:

5+m

Step-by-step explanation:

Sam is 5 years older than Michelle. This sentance tells me that we have to add. Michelle is m years old, so we can add 5+m.

Hope this helps, have a blessed day, and for any questions or comments, please ask in the comment section below!

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What is the area of the triangle whose vertices are D( 3, 3), E(3, -1), and F(-2, -5)?

ycow [4]

Answer-

Area of the triangle is 10 sq.units

Solution-

We know that,

$\text{Area of the triangle}=\dfrac{1}{2}[{x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$

Taking,

(x₁, y₁) = (3, 3)

(x₂, y₂) = (3, -1)

(x₃, y₃) = (-2, -5)

Then putting these in the formula,

$\text{Area of the triangle}=\dfrac{1}{2}[3(-1+5)+3(-5-3)-2(3+1)]$

$=\dfrac{1}{2}[3(4)+3(-8)-2(4)]$

$=\dfrac{1}{2}[12-24-8]$

$=\dfrac{1}{2}[-20]$

$=-10$

As area can not be negative, ignoring negative sign,

$\text{Area of the triangle}=10$

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3 years ago

(PLEASE HELP!) How do I solve for e? 9e^2f=49

elena55 [62]

Square root 9e^2f and 49
then divide by 9

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3 years ago

In triangle ABC, b = 600, ∠B = 11°, and ∠C = 75°. Find a.

vodomira [7]

Answer:

Step-by-step explanation:

We could use the Law of Sines if we only knew what angle A was. It just so happens that by the Triangle Angle-Sum Theorem, angle A is equal to

180 - B - C. Therefore,

angle A = 180 - 11 - 75 so

angle A = 94. And the Law of Sines is

$\frac{sin94}{a}=\frac{sin11}{600}$ and cross multiply to get

600sin94 = asin11 and solve for a:

$a=\frac{600sin94}{sin11}$ gives you that

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3 years ago

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4 years ago

The graph of F(x) can be stretched vertically and flipped over the x axis to produce the graph of G(x) if F(x)=x^2 which of the

ladessa [460]

Answer:

g(x) = -5x²

(option B)

Step-by-step explanation:

we know that our original graph, f(x) = x² is a parabola.

So, we can consider what happens when we adjust the function/equation of a parabola.

when we "vertically stretch" a parabola, we are increasing the value of x.

think of it this way: the steepness of a slope is rise over run. If we rise ten, and run one, that's going be a lot more steep than if we rise 1, run 1.

Let's say our x = 5

if f(x)=x²

f(5) = 25

> y value / steepness is 25

f(x) = 3x²

f(5) = 75

> y value / steepness is 75

So, we are looking for an equation with an increase in x present.

When a parabola has been flipped over the x-axis, we know that the original equation now includes a negative

suppose that x = 1

if y = x² ; y = 1² = 1

if y = -(x²) ; y = -(1²) ; y = -1

So, when we set x to be negative, we make our y-values end up as negative also (which makes the graph look as if it has been flipped upside-down)

This means that we are looking for a function with a negative x value.

So, we are looking for a negative x-value that is multiplied by a number >1

The graph that fits our requirements is g(x) = -5x²

hope this helps!!

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2 years ago