So, possible numbers divisible by 10.
There are 10 of them in the first 100 positive integers.
10, 20, 30, 40, 50, 60, 70, 80, 90, and 100.
And then the ones divisible by 3. There are 33.
3, 6, 9, 12, 15, 18, 21.. you get my point.
However, three of those are shared, 30, 60, and 90.
So basically add the two together and subtract three for the shared ones.
10 + 33 - 3 = 40
So there are 40 possibilities, so there is a 4/10 chance that the number is divisible by 10 or 3, so a 6/10 chance that the number is not divisible.
Or 3/5.
Answer:
E(x) = 1.43 (Approx)
Step-by-step explanation:
Given:
Total number of camera = 7
Defective camera = 5
Sample selected = 2
Computation:
when x = 0
P(x=0) = 2/7 × 1/6 = 2/42
P(x=1) = [2/7 × 5/6] + [5/7 × 2/6] = 20/42
P(x=2) = 5/7 × 4/6 = 20/42
So,
E(x) = [0×2/42] + [1×20/42] + [2×20/42]
E(x) = 1.43 (Approx)
Answer:
Actual mean: 223 pages
Predicted mean / estimate: 225 pages
Explanation below
Step-by-step explanation:
Mean = total amount ÷ # of numbers
155 + 214 + 312 + 198 + 200 + 170 + 250 + 260 + 215 + 256
Add
2,230
# of numbers = 10
2,230 ÷ 10 = 223
The exact mean is 223
If I were to predict the mean, I would say that a good estimation would be around 225, because I see that the highest number in the data set is 312, and the lowest is 155. If 312 is rounded down to 300, and 155 is rounded down to 150, the number exactly in the middle of 300 and 150 is 225.
Actual mean: 223 pages
Predicted mean: 225 pages
Hope this helps :)
25% because u have to divide the diameter of the logo to get the radius.
Answer: The correct option is (B) less than 2.
Step-by-step explanation: Given that Y varies directly with X and has a constant rate of change of 6.
We are to find the possible value of X when the value of Y is 11.
Since Y varies directly with X, so we can write
![Y\propto X\\\\\Rightarrow Y=kx~~~~~~~~~~~~~~~(i),~~~~~~~~~\textup{[where 'k' is the constant of variation]}](https://tex.z-dn.net/?f=Y%5Cpropto%20X%5C%5C%5C%5C%5CRightarrow%20Y%3Dkx~~~~~~~~~~~~~~~%28i%29%2C~~~~~~~~~%5Ctextup%7B%5Bwhere%20%27k%27%20is%20the%20constant%20of%20variation%5D%7D)
Since the rate of change is constant and is equal to 6, so we must have
So, from equation (i), we have
Now, when Y = 11, then from equation (ii), we get
Thus, the value of X is less than 2 when Y = 11.
Option (B) is CORRECT.
