The probability that he lost less than 19 pounds is 7 / 9.
According to statement
The weight loss by individual is 12 Pounds
So, by uniform distribution probability
P(c ≤ x ≤ d) = (d - c) / (b - a)
Substitute the values in it then
P(12 ≤ x ≤ 19) = (19 - 12) / (20 - 11)
P(12 ≤ x ≤ 19) = 7 / 9
So, the probability that he lost less than 19 pounds is 7 / 9.
Learn more about UNIFORM DISTRIBUTION PROBABILITY here brainly.com/question/14114556
#SPJ4
Answer:
I think it's s
Step-by-step explanation:
I think it's set equation.
Answer:
B
Step-by-step explanation:
The volume (V) of a pyramid is calculated as
V = 
area of base × perpendicular height (h)
area of square base = 12 × 12 = 144 units² and h = 8, hence
V = × 144 × 8 = 
= 384 units³ → B
Answer:
55.563
Step-by-step explanation:
Given the following :
Mean(m) point = 73
Standard deviation( sd) = 10.6
Lower 5% will not get a passing grade (those below the 5% percentile)
For a normal distribution:
The z-score is given by:
z = (X - mean) / standard deviation
5% of the class = 5/100 = 0.05
From the z - table : 0.05 falls into - 1.645 which is equal to the z - score
Substituting this value into the z-score formula to obtain the score(x) which seperates the lower 5%(0.05) from the rest of the class
z = (x - m) / sd
-1.645 = (x - 73) / 10.6
-1 645 * 10.6 = x - 73
-17.437 = x - 73
-17.437 + 73 = x
55.563 = x
Therefore, the score which seperetes the lower 5% from the rest of the class is 55.563
Let n be the number. The difference of the number and six is n-6. Then three times the difference of the number and six is 3·(n-6). This number 3·(n-6) increased by four times the number n, then
3·(n-6)=4·n.
Solve it:
3·n-3·6=4n,
3n-4n=18,
-n=18,
n=-18.
Answer: n=-18 and expression is 3·(n-6)=4·n.
