Answer:
0.865
Step-by-step explanation:
To solve for the probability we would be using the formula:
F(x) = 1 - e^−λx
Therefore, P(x > 2000) = F(x) = 1 - e^−λx
Mean = 1000 hours
λ = 1/mean = 1/1000 hours
x= 2000 hours
F(x) = 1 - e^−(1/1000)2000
F(x) = 1 - e^−2
= 0.8646647168
Therefore, the probability the the circuit will last at least 2000 hours = 0.865
Answer:
0.4077
Step-by-step explanation:
It's important to use parenthesis to avoid confusion.
9^(2x) = 6
Use exponent properties:
(9^2)^x = 6
81^x = 6
Take log of both sides
ln(81^x) = ln(6)
Use log properties:
x ln(81) = ln(6)
Solve for x:
x = ln(6) / ln(81)
x ≈ 0.4077
G(x) when x = -3 : 4 - 3(-3) = 13
2. 4
3. -11
Pinpoint the ten's place.
look at the one's place. It is a digit ≥5, round up. If it is digit <5, round down.
all the digits to the right of the ten's place becomes 0.
for example, if you are given $216.23, the ten's place is a 1. Look at the number to the right of it, the one's place is a 6, bigger than 5, so you round up, the 1 becomes a 2. the result is $220.00
if you are given $214.23, the 1 stays a 1 because 4 is smaller than 5, the result is $210.00
Answer:
Y=32
Step-by-step explanation:
