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polet [3.4K]
3 years ago
7

How do you expand (x+2)^5

Mathematics
1 answer:
just olya [345]3 years ago
4 0
Multiply
2
2
by
5
5
.
x
5
+
10
x
4
+
10
x
3
⋅
2
2
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
10
x
3
⋅
2
2
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
Raise
2
2
to the power of
2
2
.
x
5
+
10
x
4
+
10
x
3
⋅
4
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
10
x
3
⋅
4
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
Multiply
4
4
by
10
10
.
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
Raise
2
2
to the power of
3
3
.
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
8
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
8
+
5
x
⋅
2
4
+
2
5
Multiply
8
8
by
10
10
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
2
4
+
2
5
Raise
2
2
to the power of
4
4
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
16
+
2
5
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
16
+
2
5
Multiply
16
16
by
5
5
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
80
x
+
2
5
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
80
x
+
2
5
Raise
2
2
to the power of
5
5
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
80
x
+
32
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5(k+5)+4<21+6k what is the answer
Temka [501]
Solve whats in the parentheses first
5k+25+4<21+6k

5k+29<21+6k

plug in a number in k for both sides
5(1)+29<21+6(1)
5+29<21+6
34<27

5(2)+29<21+6(2)
10+29<21+12
39<33

so 5(k+5)+4 is greater than 21+6k
4 0
3 years ago
Four less than five times a number is equal to 11
SVETLANKA909090 [29]
5*3=15
15-4= 11
hope I helped:)
7 0
3 years ago
Find two numbers the quotient is between then estimate the quotient 53÷3=
zhannawk [14.2K]
16 & 18
17.6 repeating
7 0
3 years ago
In rectangle ABCD, AB = 10 cm and BC = 14 cm. If rectangle EFGH is the image after a dilation, which could be its side lengths?
lana [24]

Answer is D

After dilation the image remain same but it is stretched or shrinked to the original size.

That means the ratio of the sides and the angles between the sides remain same .

Here we did dilation of ABCD which made it to EFGH.

Hence the ratio of the corresponding sides of the original rectangle ABCD should remain same even after dilation.

the corresponding sides are : AB and EF

BC and FG

CD and GH

DA and HE

* Let us find ratio of the sides AB and BC

given that AB= 10 and BC= 14

AB/BC= 10/14 = 5 /7 ( 10 and 14 both are multiple of 2 so we reduced them by a factor of 2 )

* the raio of the corresponding sides EF and FG should be same ( 5/7)

in the option D EF= 25 and FG= 35

so EF/FG= 25/35 = 5 /7 ( both are multiple of 5 so we reduced them by the factor of 5 )

Since ratio of the corresponding sides are coming out to be same for the EFGH given in option D it should be the dilation of the ABCD

4 0
3 years ago
Read 2 more answers
A cone-shaped building has a height of 11.4 meters and a base with a diameter of 12 meters. The building will be filled with roa
Lyrx [107]
We know, Volume of a Cone = πr² h/3
v = 3.14 * (6)² * 11.4/3
v = 3.14 * 36 * 3.8
v = 429.552

Now, for 1 m³, it costs = $20
So, for 429.552 m³, it will be: 20 * 429.552 = 8591

In short, Your Answer would be $8591

Hope this helps!
3 0
3 years ago
Read 2 more answers
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