Answer:
x = 1, 3
Explanation:







Thus, there are two solutions and the values are <u>1</u> and <u>3</u>
No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.
Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

and since the relation of order "<" is transitive, this implies

find the area of the base which is 8*8=64 in^2
then the triangles one is 2*[(6*4)/2)]= 24 in^2 and theres 4 of them so times 4
24*4=96 in^2
then add and u get 160 in^2
To solve this question, I first converted one hour into minutes. (60 minutes)
Then I divided 4 1/2 into 60. As a decimal, the answer if 0.075. If you convert that into a lowest terms fraction, you get 3/40.
The general form for Pythagoras' theorem is: a² + b² = c² (where c is the longest side).
You already have sides a and b, and to figure out c, you just have to substitute the numbers into the original equation and work it out step by step. Let's substitute a for 17 and b for 24:
a² + b² = c²
(17)² + (24)² = c²
289 + 576 = c²
865 = c²
Square root both sides to work out c:
√865 = √(c²)
c = √865 ≈ 29.41