For the function
y = cos(1/2 x)
The x-intercept can be calculated by equating the function to zero and solving for x. So,
y = cos(1/2 x) = 0
1/2 x = arc cos 0
1/2 x = 90° +180°n
x =2 (90° +180°n)
x = 180° + 360°n
or converting to radians
x = (180° + 360° n)(π/180°)
x = π + 2π n
where n is any whole number
if n = 0
x = π
Therefore, the x-intercept is π or π+2π n
A=g
v=⌠g dt
v=gt+C, where C=v initial
v=gt+vi
h=⌠v dt
h=gt^2/2+vit+C, where C=h initial
h=gt^2/2+vit+hi
We are told that vi=42 ft/s, hi=0, and we know g≈-32 ft/s^2 so
h(t)=-16t^2+42t
The ball will hit the ground when h=0 so
-16t^2+42t=0
-2t(8t-21)=0, since t>0
8t-21=0
8t=21
t=21/8
t=2.625 sec
t≈2.6 sec (to nearest tenth of a second)
Answer:
H(35)=50-75/5
Step-by-step explanation:
75/5=15
50-15=35
Function f(4) = -10 and if g(x) = 2 , x = 0.
To find f(4), we will observe the graph of f(x).
According to the graph of f(x),
when x = 4, y is -10 which means when x is 4 value of f(4) is -10.
To find the value of x when g(x) is 2, we will observe the graph of g(x).
According to the graph of g(x),
when y = 2, x is 0 which means that when x is 0, the value of g(x) is 2.
Hence, f(4) is -10 and x = 0 when g(x) = 2.
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Answer:
1. 5/3
2. A
Step-by-step explanation:
