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dem82 [27]
3 years ago
14

Can someone please answer this for me

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0
The mistake she made was saying it was a $25 discount when in the equation it said adding 25, and discount is subtraction so that is the mistake.

the new equation is 9x-25=88
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yesterday the temperature was 7 degrees fahrenheit . Today the temperature is 0 degrees fahrenheit . What was the change in the
lawyer [7]

Answer:

-7

Step-by-step explanation:

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Between which two consecutive integers does ???147 lie?
BartSMP [9]
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bixtya [17]
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4 0
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I REALLY NEED HELP PLEASE!!
nadezda [96]

Answer:

To me the triangles in #6 appear to be the same shape as the first triangle in #7(EFG) with different lengths on the sides. But not much else is the same. I mean they are all triangles but the shape of the second triangle in #7(XYZ) isn't the same as either of the triangles in #6.

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4 0
3 years ago
A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year
icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 =  b(b/a)^2 = b^3/a^2

4 0
3 years ago
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