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X(^-1)^7=x^6
7(c^1)^2/3=7(c)^2/3
(m^2n^3)^-3=1/m^6n^9
Answer:
A = (5s^2t - 9st) (3t + 1)
Step-by-step explanation:
(5s^2 - 9s) (3t^2 + t)
= 15s2t^2 + 5s^2t - 27st^2 - 9st
= 5s2t (3t + 1) - 9st (3t + 1)
= ( 5s^2t - 9st) (3t+1)
Answer:
7/30
Step-by-step explanation:
5/6 = 25/30 3/5 = 18/30
25/30 - 18/30 = 7/30
Sas gives 7/30 of the ribbon to her sister.
Hope this helps! :3
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
