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blsea [12.9K]
3 years ago
6

In how many ways can a committee consisting of 4 faculty members and 5 students be formed if there are 11 faculty members and 15

students eligible to serve on the committee?
Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0
11C4 * 15C5 = \frac{11!}{4!7!} *  \frac{15!}{5!10!}= the answer.
 you can calculate that

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Which example models a negative integer A.Students in a classroom B. The age of a parent C. Money lost from a pocket D. the heig
Rufina [12.5K]

Answer:

C- Money lost from a pocket

Step-by-step explanation:

It would be C because something is decreasing ( now a negative) from what they did have.

4 0
2 years ago
Y’all mind to help a dumb asian?
insens350 [35]

Answer:

A is 62 b is 54 c is 62 and d is 62

And 7

Step-by-step explanation:

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Not sure about the second one

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State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A firm makes
Sedbober [7]

Answer:

Maximum profit at (3,0) is $27.

Step-by-step explanation:

Let  quantity of  products A=x

Quantity  of products B=y

Product A takes time on machine L=2 hours

Product A takes time on machine M=2 hours

Product B takes time on machineL= 4 hours

Product B takes time on machine M=3 hours

Machine L can used total time= 8hours

Machine M can used total time= 6hours

Profit on product A= $9

Profit on product B=$7

According to question

Objective function Z=9x+7y

Constraints:

2x+3y\leq 6

2x+4y\leq 8

Where x\geq 0, y\geq 0

I equation 2x+3y\leq 6

I equation in inequality change into equality we get

2x+3y=6

Put x=0 then we get

y=2

If we put y=0 then we get

x= 3

Therefore , we get two points A (0,2) and B (3,0) and plot the graph for equation I

Now put x=0 and y=0 in I equation in inequality

Then we get 0\leq 6

Hence, this equation is true then shaded regoin is  below the line .

Similarly , for II equation

First change inequality equation into equality equation

we get 2x+4y=8

Put x= 0 then we get

y=2

Put y=0 Then we get

x=4

Therefore, we get two points C(0,2)a nd D(4,0) and plot the graph for equation II

Point  A and C are same

Put x=0 and y=0 in the in inequality equation II then we get

0\leq 8

Hence, this equation is true .Therefore, the shaded region is below the line.

By graph we can see both line intersect at the points A(0,2)

The feasible region is AOBA and bounded.

To find the value of objective function on points

A (0,2), O(0,0) and B(3,0)

Put A(0,2)

Z= 9\times 0+7\times 2=14

At point O(0,0)

Z=0

At point B(3,0)

Z=9\times3+7\times0=27

Hence maximum value of z= 27 at point B(3,0)

Therefore, the maximum profit is $27.

6 0
3 years ago
Need help on this one
Artist 52 [7]

Answer:

12

Step-by-step explanation: it’s right

8 0
3 years ago
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