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2 years ago

HELP PLEASEEEEEEEEEEEEEEEEEE

Mathematics

2 answers:

Bezzdna [24]2 years ago

7 0

Answer:

Step-by-step explanation:

Im not completely confident but Im like 99.8% sure of it.

devlian [24]2 years ago

6 0

<u>Answer</u>

<u>Right Scalene Triangle</u>

Side a (X) = 14.91038 (To the nearest hundreth: 14.91)

Side b = 7

Side c = 13.16509

Angle ∠A = 90° = 1.5708 rad = π/2

Angle ∠B = 28° = 0.48869 rad

Angle ∠C = 62° = 1.0821 rad

Calculations:

alculated based on 2 given angles and 1 given side.

∠C = 180° - A - B = 1.0821 rad = 62°

a = b·sin(A)/sin(B) = 14.91038

c = b·sin(C)/sin(B) = 13.16509

Area =

ab·sin(C)

= 46.0778

Perimeter p = a + b + c = 35.07547

Semiperimeter s =

a + b +c

= 17.53773

Height ha =

2×Area

= 6.18063

Height hb =

2×Area

= 13.16509

Height hc =

2×Area

= 7

Median ma = √(a/2)2 + c2 - ac·cos(B) = 7.45519

Median mb = √(b/2)2 + a2 - ab·cos(C) = 13.62239

Median mc = √(c/2)2 + b2 - bc·cos(A) = 9.60884

Inradius r =

Area

= 2.62735

Circumradius R =

2sin(A)

= 7.45519

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Helpppppppppp mehhhhh plz

Goshia [24]

Let's start off with a simple y-intercept form.

y=mx + b
b represents the y intercept so we can substitute it with 2.
y = mx + 2
the point we are given, (1,1) is really just an x and y value. We can also substitute this into the equation.
y = x + 2

Now that we have some type of equation, we can convert it to the form shown in the answer choices by subtracting y from both sides.
0 = x - y + 2
Hope this helps!

4 0

2 years ago

Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$

Now we can use the identity:

sin²(x) + cos²(x) = 1

$1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1$

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

7 0

1 year ago

How far away would you need to place the ladder

hammer [34]

Answer:

Step-by-step explanation:

far away

8 0

2 years ago

Read 2 more answers

Y^2 x^3-7x = ysin(x+y)

d1i1m1o1n [39]

Answer: -54

Step-by-step explanation: 53 + 1 = 54

3 0

2 years ago

PLEASE HELP

Marat540 [252]

Answer:

Triangle DEF is a right, scalene triangle. It is not isosceles, obtuse, acute, or equilateral

Step-by-step explanation:

All we know about m and n are that they are not equal to each other and they are positive. This was given in the problem. See image. Once it is graphed you can see on the graph the lengths of DE and EF. Use Pythagorean theorem to calculate DF. see image.

DE is horizontal and EF is vertical, so you can see their slopes or calculate using a formula. Calculate the slope of DF. Slope is y-y on top of a fraction and x-x on the bottom of the fraction.

Lastly, use midpoint formula to find the midpoints. Average the x's and average the y's to find the x- and y-coordinates of the midpoints. See image.

Finally, DEF is a right triangle. The graph as well as the slopes show us that DE and EF form a right angle. So DEF must be a right triangle (and not obtuse nor acute) We were told that m doesNOT equal n, so the triangle cannot have two equal sides, so it cannot be isosceles (2 equal sides) nor equilateral (3 equal sides) It has 3 different lengths of sides; that is called scalene.

4 0

1 year ago