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otez555 [7]
3 years ago
7

 If the hypotenuse of a right triangle is 2 cm and one leg is √ 3 cm, the exact length of the other leg is

Mathematics
1 answer:
beks73 [17]3 years ago
8 0
The answer would be B. 1 because by using the pythagorean theorem ((a^2)+(b^2)=(c^2)) on this right triangle, (a^2)=((sqrt(3))^2)=3, (b^2)=?(let's use x), and (c^2)=(2^2)=4. So, (c^2)-(a^2)=(b^2). 4-3=1 and (sqrt(1))=1.
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Solve 8x+2y=13 and 4x+y=11 using substitution
Aleonysh [2.5K]

Answer:

No Solution

Step-by-step explanation:

8x+2y=13                         4x+y=11               Subtract 4x on both sides to isolate y

                                        y=-4x+11       <---- Substitute this equation into the                                            

                                                                     equation 8x+2y=13

8x+2(-4x+11)=13

8x-8x+22=13

22=13 (not true)

No Solution          

                     

4 0
3 years ago
A square-shaped patio has an area of 256ft squared. What are the dimensions of the patio?
olga nikolaevna [1]

Answer:

all sides are 16 ft

Step-by-step explanation:

If the side length is x, the area is x²=256, hence x = √256 = 16

8 0
3 years ago
What's bigger 2/3 or 4/5
Eduardwww [97]
The best thing to do is either to find a common denominator or convert them to decimals.
I will find a common denominator.
A common denominator of 3 and 5 is 15.
You multiply the first fraction by 5
2*5= 10
This then becomes 10/15
You then multiply the second by 3.
4*3= 12
Therefore, this becomes 12/15
As the second of these fractions is larger, this means that 4/5 is larger.
The alternative method is to put them into decimals, in which case 2/3= 0.66 and 4/5= 0.8
Hope this helps :) 
4 0
3 years ago
Read 2 more answers
The total interest paid on a 3​-year loan at 9​% interest compounded monthly is ​$1505.82 determine the monthly payment for the
Kruka [31]
Number of compounding periods is
n=12months×3years=36
I assume that

The total interest=
monthly payment×number of compounding periods - the amount of the present value of an annuity ordinary
I=x×n-pv

Let monthly payment be X

I =Total interest is 1505.82

The present value of an annuity ordinary is
Pv=X [(1-(1+0.09/12)^(-36))÷(0.09/12)]

now plug those in the formula of the total interest above
I=x×n-pv
1505.72=36X-X [(1-(1+0.09/12)^(-36))÷(0.09/12)]
Solve for X using Google calculator to get the monthly payment which is
X=330.72

Check your answer using the interest formula
36×330.72−330.72×((1−(1+0.09
÷12)^(−12×3))÷(0.09÷12))
=1,505.83



3 0
3 years ago
8.9537 to three decimal places , two d.p , one d.p
Kryger [21]
8953.7 is the answer to this
6 0
3 years ago
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