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ivann1987 [24]
2 years ago
7

What is the area of this triangle?

Mathematics
1 answer:
kogti [31]2 years ago
8 0
What triangle lol.....
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Help me<br><br>6 = 1/5 (4y + 10)​
gregori [183]

Step-by-step explanation:

open the bracket

6={(1/5×4y) + 1/5×10}

6=4/5y+2

6-2=4/5y

4=4/5y

divide both sides by 4/5

y=1/5

4 0
3 years ago
Read 2 more answers
What’s Distribute -x(5x+2)
MaRussiya [10]

Answer:

-5x^2-2x

Step-by-step explanation:

When distributing, you multiply the term outside the brackets to all the terms in brackets.

If the term outside the bracket is negative, then when distributing/opening the brackets, the signs of the terms changes.

So in this prob. -x would multiply to both +5x and +2

-x*5x+-x*2

∴-5x^2-2x

4 0
3 years ago
Read 2 more answers
Find the area of a trapezoid with base 1 side = 10 base 2 side = 16 and 3​
mart [117]

Answer:

Area of Trapezoid is 39 unit²

Step-by-step explanation:

Given as :

For A Trapezoid

The measure of base side 1 = b_1 = 10 unit

The measure of base side 2 = b_2 = 16 unit

The height of the Trapezoid = h = 3 unit

Let  The Area of Trapezoid = A square unit

<u>Now, From Formula</u>

Area of Trapezoid = \dfrac{1}{2} × (sum of opposite base) × height

I.e A =  \dfrac{1}{2} × (b_1 + b_2) × h

Or, A =  \dfrac{1}{2} × (10 unit + 16 unit) × 3 unit

Or, A =  \dfrac{1}{2} × (26 unit) × 3 unit

Or, A =  \dfrac{1}{2} × 78 unit²

Or, A = \dfrac{78}{2} unit²

I.e A = 39 unit²

So, The Area of Trapezoid = A = 39 unit²

Hence, The Area of Trapezoid is 39 unit² . Answer

6 0
3 years ago
F(7)=3/x+2-squar root x-3
leonid [27]
Insert x = 7
so 3/(7+2) - sqr (7-3)
=3 / (9) - sqr (4)
= 1/3 - 2
=1/3 - 6/3
= -5/3
8 0
3 years ago
Express 0.000000298 in scientific notation
Olenka [21]
The expression would be 2.98 * 10 to the -7 power? Please tell me if I'm wrong.
5 0
3 years ago
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